All categories

3 years ago

explain how the efficiency of an ideal meachine compares with the efficiency of a real machine. For 25 POINTS

2 answers:

7 0

An ideal machine is 100% efficient, meaning it puts out all of the energy you put in (ie. no loss due to friction..) A real machine can never be 100% efficient. You must always put more energy Into a real machine than you get out of it.

Tcecarenko [31]3 years ago

5 0

The efficiency of such a machine is 100%. An ideal machine is one in which no part of the input energy to the machine gets wasted and the whole input energy is converted into the useful work. The efficiency of such a machine is 100%.
PLEASE MARK ME AS BRAINLIEST CAUSE IVE NEVER GOT BRAINLIEST BEFORE AND HAVE A GOOD DAY !

You might be interested in

Is this a testable question?

faltersainse [42]

This is a non testable question because it cannot be answered by doing an experiment. But it could be modified for example Dogs are more obedient then cats.

8 0

3 years ago

Read 2 more answers

Sarah walks WEST a distance of 5 meters then turns NORTH and walks 8

Leokris [45]

Answer:

she is 3 meters in north

Explanation:

3 0

3 years ago

Which of the following best describes resistance?

kicyunya [14]

B. Impedes the flow of electrons

7 0

3 years ago

What service is provided for HIV testing and what’s the important of this service?

svetlana [45]

Answer:

HIV Testing Services is an entry point to HIV prevention, treatment, care and support. It is expected that when people know their HIV status they will make informed choice on HIV prevention or if positive, access other services. Testing yourself for HIV is important for your health, your relationships, your life and your future. The growth of new infections continues to pose serious health risks. ... The fact is that HIV is preventable, and you can reduce or eliminate your risk. And early detection can lead to early treatment and better outcomes.

7 0

3 years ago

1. Calcular la masa de mercurio que pasó de 30 °C hasta 120 °C y absorbió 4400 cal. Calor específico del

timofeeve [1]

Answer:

Masa, m = 0.088 kg

Explanation:

Given the following data;

Temperatura inicial = 30°C

Temperatura final = 120°C

Capacidad calorífica específica = 138J/kg.K

Calor absorbido, Q = 4400 cal.

Para encontrar la masa;

La capacidad calorífica viene dada por la fórmula;

$Q = mct$

Dónde;

Q representa la capacidad calorífica o la cantidad de calor.

m representa la masa de un objeto.

c representa la capacidad calorífica específica del agua.

dt representa el cambio de temperatura.

dt = T2 - T1

dt = 120 - 30

dt = 90°C to kelvin = 273 + 90 = 363K

Sustituyendo en la fórmula, tenemos;

$4400 = m*138*363$

$4400 = 50094m$

$m = \frac {4400}{50094}$

Masa, m = 0.088 kg

7 0

3 years ago