All categories

2 years ago

explain how the efficiency of an ideal meachine compares with the efficiency of a real machine. For 25 POINTS

2 answers:

7 0

An ideal machine is 100% efficient, meaning it puts out all of the energy you put in (ie. no loss due to friction..) A real machine can never be 100% efficient. You must always put more energy Into a real machine than you get out of it.

Tcecarenko [31]2 years ago

5 0

The efficiency of such a machine is 100%. An ideal machine is one in which no part of the input energy to the machine gets wasted and the whole input energy is converted into the useful work. The efficiency of such a machine is 100%.
PLEASE MARK ME AS BRAINLIEST CAUSE IVE NEVER GOT BRAINLIEST BEFORE AND HAVE A GOOD DAY !

You might be interested in

A student pushes a 2.85 kg cart causing it to accelerate at a rate of 4.9 m/s squared .What amount of force must the student hav

uysha [10]

In order to find the force (F), you would have to use the formula for it:
F=ma
where m is mass and a is acceleration.
In the problem, the mass is 2.85kg and the acceleration is 4.9m/s^2.
Therefore,
F=2.85kg(4.9m/s^2)
F=13.965kg(m/s^2)
Since N=kg(m/s^2)
F=13.965N
And because the problem requires that we use only 2 significant figures,
F=13N
Therefore, the student must exert 13N of force.

7 0

3 years ago

A train whistle has a sound intensity level of 70. dB, and a library has a sound intensity level of about 40. dB. How many times

kodGreya [7K]

Answer:

The sound intensity of train is 1000 times greater than that of the library.

Explanation:

We have expression for sound intensity level,

$L=10log_{10}\left ( \frac{I}{I_0}\right )$

A train whistle has a sound intensity level of 70 dB

We have

$70=10log_{10}\left ( \frac{I_1}{I_0}\right )$

A library has a sound intensity level of about 40 dB

We also have

$40=10log_{10}\left ( \frac{I_2}{I_0}\right )$

Dividing both equations

$\frac{70}{40}=\frac{10log_{10}\left ( \frac{I_1}{I_0}\right )}{10log_{10}\left ( \frac{I_2}{I_0}\right )}\\\\\frac{7}{4}=\frac{log_{10}\left ( \frac{I_1}{I_0}\right )}{log_{10}\left ( \frac{I_2}{I_0}\right )}\\\\10^7\frac{I_2}{I_0}=10^4\frac{I_1}{I_0}\\\\\frac{I_1}{I_2}=10^3=1000$

The sound intensity of train is 1000 times greater than that of the library.

3 0

2 years ago

An electromagnetic wave has a frequency of 1.0 x 10^5. What is the wavelength of the wave?

SashulF [63]

Answer:

The frequency , speed and wavelength of an electromagnetic wave are related by the formula

Speed = frequency x wavelength

frequency = speed / wavelength

substituting the values

frequency = 3 x #10 ^8# m /s / 1 x #10^15# m

= 3 x #10^-7# /s

6 0

2 years ago

Read 2 more answers

What is the frequency of a sound wave directly related to?

Mama L [17]

The frequency of a sound wave is the number of cycles of a sound wave per second or Hertz (Hz). The frequency can be calculated by dividing wavelength by time (Figure 1.3). A small wavelength will yield a higher frequency, whereas a larger wavelength will yield a smaller frequency.

8 0

3 years ago

If you were to apply a force of 15N to a medicine ball with a mass of 10kg, what would its acceleration be

tresset_1 [31]

One of the equations for force is: Force = mass × acceleration.

The force and mass are given and so:

F=15N

m=10kg

By plugging in these values we obtain:

$F=ma\\\\15=10(a)\\$

$\frac{15}{10}=\frac{10(a)}{10}\\\\a=\frac{15}{10}=1.5m/s^2$

So the acceleration is a=1.5m/s^2

6 0

3 years ago