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coldgirl [10]
4 years ago
9

A car travels 40 miles in 30 min. Calculate the car's average speed in mi/hr.

Physics
2 answers:
Law Incorporation [45]4 years ago
8 0
Speed = distance by time
your time is 30 min or 0.5h
you speed is 40 miles divided by 0.5h equals 80 miles per hour 

answer is 80mi/hr
Ivenika [448]4 years ago
7 0
1.33 is the answer
40/30 is 1.33
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nataly862011 [7]

Explanation:

Given:

v_0 = 28.0\:\text{ft/s}

v = 50.0\:\text{ft/s}

t = 7.40\:\text{s}

First, we calculate the acceleration of the car during this time:

v = v_0 + at \Rightarrow a = \dfrac{v - v_0}{t}

Plugging in the given values, we get

a = \dfrac{50.0\:\text{ft/s} - 28.0\:\text{ft/s}}{7.40\:\text{s}} = 2.97\:\text{ft/s}^2

Now that we have the value for the acceleration, we can solve for the distance traveled during the time t:

x = v_0t + \frac{1}{2}at^2

\:\:\:\:=(28.0\:\text{ft/s})(7.40\:\text{s})

\:\:\:\:\:\:\:\:\:\:\:\:+ \frac{1}{2}(2.97\:\text{ft/s}^2)(7.40\:\text{s})^2

\:\:\:\:= 289\:\text{ft}

7 0
3 years ago
A cart of mass M is attached to an ideal spring that can stretch and compress equally well. The cart and spring rest on a smooth
Alexxx [7]

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( File has been attached)

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3 years ago
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ANEK [815]

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Explanation:

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6 0
3 years ago
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Lesechka [4]

Answer:

0.55 m/s

Explanation:

Parameters given:

Mass of lighter car, m = 1400 kg

Mass of heavier car, M = 1850 kg

Initial speed of lighter car, u = -1.10 m/s (since it's moving to the left)

Initial speed of heavier car, U = 1.5 m/s

Final sped of heavier car, V = 0.25 m/s

Using the principle of conservation of momentum, total initial momentum is equal to total final momentum:

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Inputting the values:

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1235 = 1400v + 462.5

1400v = 772.5

v = 772.5/1400

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Answer:

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3 years ago
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