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4 years ago

Boron (B): 1sE2sF2pG E = F = G =

Chemistry

2 answers:

Shkiper50 [21]4 years ago

5 0

Answer:

e= 2

f= 2

g= 1

Explanation:

stellarik [79]4 years ago

3 0

Answer:

E = 2

F = 2

G = 1

Explanation:

Just did edgenuity.

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Answer:

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3 years ago

What are 2 scientist classify organisms into groups

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3 years ago

How many g of CO2 can be produced from 256 g Fe2O3?

kotykmax [81]

Answer:

if i consider this reaction

Fe2O3+ 3CO---》2Fe+ 3CO2

so let's calculate first moles of Fe2O3 i.e. = 256/159.69= 1.6 moles

So the one moles of Fe2O3 is forming three moles of CO2

hence 1.6 moles will form 4.8 moles of CO2

one mole of CO2 is 44 g so 4.8 moles of Co2 is 44×4.8= 211.2 g

so the conclusion is 211.2 g of CO2 can be produced from 256 g Fe2O3!!

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3 years ago

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3 years ago

Place the following transitions of the hydrogen atom in order from longest to shortest wavelength of the photon emitted. Rank fr

gizmo_the_mogwai [7]

Answer:

7 to 4 (higher $\lambda$ )

5 to 3

3 to 2

4 to 2 (lower $\lambda$ )

Explanation:

We can use the Rydberg formula which relates the wavelength of the photon emissions to the principle quantum numbers involved in the transition:

$\frac{1}{\lambda}=R((\frac{1}{n_1^2})-(\frac{1}{n_2^2}))$

with $n_1$ final n, and $n_2$ initial n

evaluating for each transition:

7 to 4 $\frac{1}{\lambda} = R((\frac{1}{4^2})-(\frac{1}{7^2}))= R(1/16-1/49)=R(0.042)$

5 to 3 $\frac{1}{\lambda}= R(1/9-1/25)=R(0.071)$

4 to 2 $\frac{1}{\lambda}= R(1/4-1/16)=R(0.1875)$

3 to 2 $\frac{1}{\lambda}= R(1/4-1/9)=R(0.139)$

Note that the above formula is written for $\frac{1}{\lambda}$ , so lower $\frac{1}{\lambda}$ value obtained involves higher $\lambda$ .

So we should order from lower to higher $\frac{1}{\lambda}$

7 to 4 (higher $\lambda$ )

5 to 3

3 to 2

4 to 2 (lower $\lambda$ )

Note: Take into account that longer wavelength involves lower energy ( $E=\frac{hc}{\lambda}$ ).

3 0

3 years ago