Answer:
AgC2H3O2 is: Silver acetate
Answer:
pH = 12.20
Explanation:
Ca(OH)2 is a strong base, so it dissociates completely. A 0.08 M solution of Ca(OH)2 is 0.16 M OH-, since every mole of Ca(OH)2 has 2 OH-.
Calculate pOH using [OH-] = 0.16 M
pOH = -log(0.16) = 0.80
pH = 14 - pOH = 14 - 0.80 = 12.20
200.0 mL =0.2000 L
Molarity = number of mole solute / volume solution(L) = 0.50 mol/0.2000 L=
= 2.5 mol/L =2.5M
Answer : 2.5 M