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egoroff_w [7]
3 years ago
10

What mass of magnesium oxide is formed when 48.62g of magnesium is reacted with excess oxygen?

Chemistry
1 answer:
marin [14]3 years ago
5 0

Answer: -

81.03 g magnesium oxide is formed when 48.62g of magnesium is reacted with excess oxygen

Explanation: -

Atomic mass of Mg = 24 g

Molar mass of MgO = 24 x 1 + 16 x 1

= 40 g

The balanced chemical equation for this reaction is

2 Mg + O₂ → 2MgO

From the balanced chemical equation we see

2 mol of Mg gives 2 mol of MgO.

2 x 24 g of Mg gives 2 x 40g of MgO.

48.62 g of Mg gives \frac{2 x 40 g MgO}{2 x 24 g Mg} x Mg

= 81.03g of MgO

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                      %age Yield =   96 %

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Step 2: <u>Find out moles of BaSO₄ formed:</u>

According to balance chemical equation,

                  1 mole of Ba(NO₃)₂ produced  =  1 mole of BaSO₄

So,

        0.2873 moles of Ba(NO₃)₂ will produce  =  X moles of BaSO₄

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                      X =  0.2873 mol × 1 mol / 1 mol

                       X =  0.2873 moles of BaSO₄

Step 3: Calculate Theoretical Mass of BaSO₄:

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                  %age Yield  =  <u>???</u>

Formula Used:

                   %age Yield  =  (Actual Yield ÷ Theoretical Yield) × 100

Putting Values,

                   %age Yield  =  (64.4 g ÷ 67.07 g) × 100

                   %age Yield =  96.01 % ≈ 96 %

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