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likoan [24]
3 years ago
9

Whenever you push an object across a frictional surface, it starts out taking a lot of force to push to get the object moving. H

owever, once the object starts moving, it is much easier to keep it moving. What does this tell you about one of the main differences between static and kinetic friction?
a.Static friction only depends on the surface material, while kinetic friction only depends on the motion

b Kinetic and Static friction are the exact same thing

c Static friction and kinetic friction are combined in one at all times, but static friction is just not seen during the motion

d Static Friction is much stronger than kinetic friction, so it takes more force to get an object moving than it does to keep it moving
Physics
1 answer:
son4ous [18]3 years ago
5 0

Answer:

The answer is A

Explanation:

Here's an example. A child is in school taking a test. They have made a mistake on a question, and want to erase it. The eraser is made out of a type of rubber, the rubber has friction, which means the eraser has something that's going to resist movement. Now the child has exerted enough force to get it moving, and it's moving, it won't stop unless the child stops exerting force to keep it moving. Both Newton's 1st and 3rd law explain the action of moving something on a surface with friction.

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Suppose we have two planets with the same mass, but the radius of the second one is twice the size of the first one. How does th
bogdanovich [222]

The free-fall acceleration on the second planet is one-fourth the value of the first planet.

Calculation:

Consider the mass of planet A to be, M

               the mass of planet B to be, Mₓ = M

               the radius of planet A to be, R₁

               the radius of planet B to be, R₂

The acceleration due to gravity on planet A's surface is given as:

g = GM/R₁²      - (1)

Similarly, the acceleration due to gravity on planet B's surface is given as:

g' = GM/R₂²                           [where, R₂ = 2R₁]

   = GM/4R₁²    -(2)

From equation 1 & 2, we get:

g/g' = GM/R₁² ÷ GM/4R₁²

g/g' = 4/1

Thus we get,

g' = 1/4 g

Therefore, the free-fall acceleration on the second planet is one-fourth the value of the first planet.

Learn more about free-fall here:

<u>brainly.com/question/13299152</u>

#SPJ4

6 0
2 years ago
A block of lead has dimensions of 4.50 cm by 5.20 cm by 6.00 cm. The block weighs 1587 g. From this information, calculate the d
mamaluj [8]

Answer:

11.3 g/cm^3

Explanation:

density = mass/volume

volume of rectangular prism = length * width * height

volume = (4.50 cm)(5.20 cm)(6.00 cm) = 140.4 cm^3

mass = 1587 g

density = (1587 g)/(140.4 cm^3)

density = 11.3 g/cm^3

6 0
3 years ago
Alice climbs 100 meters directly up the face of a cliff to reach the summit. Her friend Peter hikes the long way around taking a
SOVA2 [1]

Answer:

Alice Distance = 100 meters

Peter's Distance = 3 km

Alice Displacement and Peter's displacement are both 100 meters upwards.

Explanation:

To solve this question, we have to first define distance and displacement.

Distance is simply the measurement of the sum of all paths travelled from one point to another while displacement is measurement of the shortest distance from initial point to final point.

Now, Alice and Peter are moving from the same point.

Alice distance travelled is 100 meters.

Also, her displacement will be 100 meters because it is the shortest distance to the summit of the cliff.

Now, for Peter, he decides to take a longer route which is 3 km in distance.

However, the shortest path which is the displacement is still 100 meters.

Thus, Peter's displacement is 100 meters.

4 0
3 years ago
A gray kangaroo can bound across level ground with each jump carrying it 9.6 m from the takeoff point. Typically the kangaroo le
xz_007 [3.2K]

Answer:

(A) 11 m/s

(B) 1.3 m

Explanation:

Horizontal range, R = 9.6 m

Angle of projection, theta = 28 degree

(A)

Use the formula of horizontal range

R = u^2 Sin 2 theta / g

u^2 = R g / Sin 2 theta

u^2 = 9.6 × 9.8 / Sin ( 2 × 28)

u = 10.65 m/s

u = 11 m/s

(B)

Use the formula for maximum height

H = u^2 Sin ^2 theta / 2g

H =

10.65 × 10.65 × Sin^2 (28) / ( 2 × 9.8)

H = 1.275 m

H = 1 .3 m

4 0
3 years ago
A bicycle with an initial velocity of +6 m/s accelerates at a rate of +2 m/s2 for 3 seconds. What distance does the bicycle trav
irga5000 [103]

Answer:

27 m

Explanation:

Given:

v₀ = 6 m/s

a = 2 m/s²

t = 3 s

Find: Δx

Δx = v₀ t + ½ at²

Δx = (6 m/s) (3 s) + ½ (2 m/s²) (3 s)²

Δx = 27 m

3 0
3 years ago
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