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Taya2010 [7]
3 years ago
8

Which type of soda has more sugar?

Physics
1 answer:
scoray [572]3 years ago
3 0

Answer:

The top-ranked among popular soda brands in America is Mountain Dew, which has 3.83 grams of sugar per fl. oz., bringing a 12 fl. oz. can to a whopping 46 grams of sugar.

Explanation:

The sugar content is the main factor that makes Mountain Dew worse than other sodas. One serving of “The Dew” has 11 teaspoons of sugar. One serving of Coca Cola only has 9 grams of sugar, which is a lot already. Mountain Dew also has a lot of citric acid in it, which will soften your enamel.

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What is the distance covered in 20 minutes by a train traveling 500m/m?
MrMuchimi

Answer:

answer is 10km

Explanation:

use "S =Ut "

S=distance U=velocity t =time

no need to convert time into seconds as the velocity has given in meters per minute

3 0
4 years ago
A 12.0kg microwave oven is pushed 14.0m up the sloping surface of a loading ramp inclined at an angle 37 degrees above the horiz
Semenov [28]

Answer:

Answered

Explanation:

a) What is the work done on the oven by the force F?

W = F * x

W = 120 N * (14.0 cos(37))

<<<< (x component)

W = 1341.71

b) F_f=\mu_k N

F_f=0.25\times12\times9.8

= 29.4 N

W_f= F_f\times x

W_f= 29.0\times 14 cos(37)

W_f= 328.72 J = 329 J

c) increase in the internal energy

U_2 = mgh

= 12*9.81*14sin(37)

= 991 J

d) the increase in oven's kinetic energy

U_1 + K_1 + W_other = U_2 + K_2

0 + 0 + (W_F - W_f ) = U_2 + K_2

1341.71 J - 329 J - 991 J = K_2

K_2 = 21.71 J

e) F - F_f = ma

(120N - 29.4N ) / 12.0kg = a

a = 7.55m/s^2

vf^2 = v0^2 + 2ax

vf^2 = 2(7.55m/s)(14.0m)  

V_f = 14.5396m/s

K = 1/2(mv^2)

K = 1/2(12.0kg)(14.5396m/s)

K = 87.238J

4 0
3 years ago
What does the slope of a velocity versus time graph represent?​
liberstina [14]
The slope represents the acceleration
7 0
3 years ago
How many electrons circulate each second through the cross section of a conductor, which has a current intensity of 4A.
guajiro [1.7K]

Answer:

2.5×10¹⁹

Explanation:

4 C/s × (1 electron / 1.60×10⁻¹⁹ C) = 2.5×10¹⁹ electrons/second

8 0
4 years ago
6. A 1,780kg car moving at 14m/s takes a turn around a circle with a radius of 50.0m.
m_a_m_a [10]

1) Centripetal acceleration: 3.9 m/s^2

2) Centripetal force: 6942 N

Explanation:

1)

For an object moving in uniform circular motion (=circular motion with constant  speed), the net acceleration is the centripetal acceleration, directed towards the centre of the trajectory and whose magnitude is given by

a=\frac{v^2}{r}

where

v is the speed

r is the radius of the circle

For the car in this problem, we have

v = 14 m/s is the speed

r = 50.0 m is the radius

Substituting, we find the acceleration:

a=\frac{14^2}{50.0}=3.9 m/s^2

2)

The net force acting upon the car is the centripetal force, also acting towards the centre of the circular path, and whose magnitude is given by

F=ma

where

m is the mass

a is the centripetal acceleration

For the car in this problem, we have:

m = 1780 kg is the mass

a=3.9 m/s^2 is the acceleration

Substituting, we find the centripetal force:

F=(1780)(3.9)=6942 N

Learn more about centripetal acceleration and force:

brainly.com/question/2562955

#LearnwithBrainly

6 0
3 years ago
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