Answer:
+
*LN(|
|) +C
Step-by-step explanation:
we will have to do a trig sub for this
use x=a*tanθ for sqrt(x^2 +a^2) where a=2
x=2tanθ, dx= 2 sec^2 (θ) dθ
this turns
into integral(sqrt( [2tanθ]^2 +4) * 2sec^2 (θ) )dθ
the sqrt( [2tanθ]^2 +4) will condense into 2sec^2 (θ) after converting tan^2(θ) into sec^2(θ) -1
then it simplifies into integral(4*sec^3 (θ)) dθ
you will need to do integration by parts to work out the integral of sec^3(θ) but it will turn into (1/2)sec(θ)tan(θ) + (1/2) LN(|sec(θ)+tan(θ)|) +C
then you will need to rework your functions of θ back into functions of x
tanθ will resolve back into
(see substitutions) while secθ will resolve into
sec(θ)=
is from its ratio identity of hyp/adj where the hyp. is
and adj is 2 (see tan(θ) ratio)
after resolving back into functions of x, substitute ratios for trig functions:
=
+
*LN(|
|) +C
<span><span>Step by step is like....:
(<span><span><span>3<span>x2</span></span>+<span>2x</span></span>−3</span>)</span><span>(<span>x−1</span>)</span></span><span>
=<span><span>(<span><span><span>3<span>x2</span></span>+<span>2x</span></span>+<span>−3</span></span>)</span><span>(<span>x+<span>−1</span></span>)</span></span></span><span>
=<span><span><span><span><span><span><span>(<span>3<span>x2</span></span>)</span><span>(x)</span></span>+<span><span>(<span>3<span>x2</span></span>)</span><span>(<span>−1</span>)</span></span></span>+<span><span>(<span>2x</span>)</span><span>(x)</span></span></span>+<span><span>(<span>2x</span>)</span><span>(<span>−1</span>)</span></span></span>+<span><span>(<span>−3</span>)</span><span>(x)</span></span></span>+<span><span>(<span>−3</span>)</span><span>(<span>−1</span>)</span></span></span></span><span>
=<span><span><span><span><span><span>3<span>x3</span></span>−<span>3<span>x2</span></span></span>+<span>2<span>x2</span></span></span>−<span>2x</span></span>−<span>3x</span></span>+3</span></span><span>
=<span><span><span><span>3<span>x3</span></span>−<span>x2</span></span>−<span>5x</span></span>+<span>3
Hoped I helped!</span></span></span>
It’s is even bc it doesn’t go through the origin
-10 and 2
-10 x 2 = -20
-10 + 2 = -8
Answer:

Step-by-step explanation:
So we have the equation:
. and I'm assuming you meant to do mixed fractions and not actually multiplying. 2 * 2/3. So the first thing to do is follow PEMDAS which essentially says Parenthesis first, Exponents next, Multiplication or Division, and then Addition or Subtract. So let's start by evaluating the 2 2/3 and 1 1/2. The first step is to combine 2 into the 2/3 and the 1 into 1/2. This is done by multiplying the 2 by the denominator of 3, and adding it to the numerator so:
. And you do this for the 1/2 as well:
.
Now when adding fractions, you can only add them when they have the same denominator, so we have the get 3/2 and 8/3 to have the same denominator. You can list the multiplies of 2 and 3 to try to find a LCM, but in this case, I'll just multiply 2 and 3, since they're really small numbers, also because 6 is the LCM.
. And now do this to the 3/2 you get:
. Now the inside of the parenthesis is:
. So now we have the equation:
. Also notice how I got ride of the plus sign and made it negative? Think of it as having a 1 in front and simply distributing that to the -7, 1*(-7) becomes -7.
Now to multiply the fraction by a whole number you simply multiply the denominator and numerator, and you can think of the denominator of a whole number as a 1. So this gives you:
. Now we have the equation:
. And to subtract these two numbers I'll make the 3 1/2 a fraction by multiplying the 3 by the denominator and adding it to the 1 which should become 7/2. And after that multiply both sides by 3/3 to get 21/6 so they have the same denominator. This gives you the equation:
. Which can simplify by dividing both sides by 2 to get: 