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3 years ago

1ooooooooooooooooooooooooooox387477918237187872811778237248548793948878484737489

Mathematics

1 answer:

Elis [28]3 years ago

3 0

Answer: I believe the answer to that question is no

Step-by-step explanation: So you see, when there are not symbols that represent addition or subtraction, or any other operation, it's not considered a question.

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The rate a car travels varies inversely with the time of the trip. If a car traveling 63 miles per hour can make the

Dahasolnce [82]

Answer:

2.25 hours

Step-by-step explanation:

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3 years ago

Ian puts 300.00 into an account to use for school expenses the account earns 6%interest compounded annually how much will be in

romanna [79]

This problem is about componded interest. The formula for compounded interest is:

$\begin{gathered} \text{Amount}=\text{Initial}\cdot(1+r)^t \\ \text{Where,} \\ \text{Amount is the total acumulative at time t.} \\ \text{Initial is the initial amount, at t=0} \\ r\text{ is the interest in decimal number.} \\ t\text{ is the time accordingly the interest, in this case is in years.} \end{gathered}$

In this case, Initial = 300, r = 0.06 and t=10 so the total amount in the account after 10 years is:

$\begin{gathered} \text{Amount}=300\cdot(1+0.06)^{10} \\ \text{Amount}=300\cdot1.06^{10} \\ \text{Amount}=300\cdot1.79085 \\ \text{Amount}=537.255 \end{gathered}$

The amount after 10 years is 573.26.

4 0

1 year ago

PLEASE HELP!!!!

Lilit [14]

Answer:

just took the test

Step-by-step explanation:

8 0

3 years ago

describe the steps you would follow to write a two step equation you can use to solve a real world problem

RideAnS [48]

Pretend the equation was 2x - 4 > 8
The first step (of the two) would be to add 4 to the (-4) and to the other side of the equation (+4) to the 8, first. (You wouldn't use the number with variable in the first step) Then you would rewrite the equation: 2x > 12 (it's now 12 because you added the 4 to the 8). The second step is to divide 2x by 2x and do the same with 12. By dividing both sides with the coefficient, will help find "x". 12/2 is 6, therefore x > 6. (the last step would be to graph the expression if needed to)

7 0

3 years ago

Weights and heights of turkeys tend to be correlated. For a population of turkeys at a farm, this correlation is found to be 0.6

LenaWriter [7]

Answer:

a turkey at the farm which weighs more than 90% of all the turkeys is predicted to be taller than <u>79.37 %</u> of them.

The average height for turkeys at the 90th percentile for weight is 34.554

Of the turkeys at the 90th percentile for weight, roughly the percentage that would be taller than 28 inches 79.37%

Step-by-step explanation:

Given that:

For a population of turkeys at a farm, the correlation found between the weights and heights of turkeys is r = 0.64

the average weight in pounds $\overline x$ = 17

the standard deviation of the weight in pounds $S_x$ = 5

the average height in inches $\overline y$ = 28

the standard deviation of the height in inches $S_y$ = 8

Also, given that the weight and height both roughly follow the normal curve

For this study , the slope of the regression line can be expressed as :

$\beta_1 = r \times ( \dfrac{S_y}{S_x})$

$\beta_1 = 0.64 \times ( \dfrac{8}{5})$

$\beta_1 = 0.64 \times 1.6$

$\beta_1 = 1.024$

To the intercept of the regression line, we have the following equation

$\beta_o = \overline y - \beta_1 \overline x$

replacing the values:

$\beta_o = 28 -(1.024)(17)$

$\beta_o = 28 -17.408$

$\beta_o = 10.592$

However, the regression line needed for this study can be computed as:

$\hat Y = \beta_o + \beta_1 X$

$\hat Y = 10.592 + 1.024 X$

Recall that;

both the weight and height roughly follow the normal curve

As such, the weight related to 90th percentile can be determined as shown below.

Using the Excel Function at 90th percentile, which can be computed as:

(=Normsinv (0.90) ; we have the desired value of 1.28

∴

$\dfrac{X - \overline x}{s_x } = 1.28$

$\dfrac{X - 17}{5} = 1.28$

$X - 17 = 6.4$

X = 6.4 + 17

X = 23.4

The predicted height $\hat Y = 10.592 + 1.024 X$

where; X = 23.4

$\hat Y = 10.592 + 1.024 (23.4)$

$\hat Y = 10.592 + 23.9616$

$\hat Y = 34.5536$

Now; the probability of predicted height less than 34.5536 can be computed as:

$P(Y < 34.5536) = P( \dfrac{Y - \overline y }{S_y} < \dfrac{34.5536-28}{8})$

$P(Y < 34.5536) = P(Z< \dfrac{6.5536}{8})$

$P(Y < 34.5536) = P(Z< 0.8192)$

From the Z tables;

P(Y < 34.5536) =0.7937

Hence, a turkey at the farm which weighs more than 90% of all the turkeys is predicted to be taller than <u>79.37 %</u> of them.

The average height for turkeys at the 90th percentile for weight is :

$\hat Y = 10.592 + 1.024 X$

where; X = 23.4

$\hat Y = 10.592 + 1.024 (23.4)$

$\hat Y = 10.592 + 23.962$

$\mathbf{\hat Y = 34.554}$

Of the turkeys at the 90th percentile for weight, roughly what percent would you estimate to be taller than 28 inches?

i.e

P(Y >28) = 1 - P (Y< 28)

$P(Y >28) = 1 - P( Z < \dfrac{28 - 34.554}{8})$

$P(Y >28) = 1 - P( Z < \dfrac{-6.554}{8})$

$P(Y >28) = 1 - P( Z < -0.8193)$

From the Z tables,

$P(Y >28) = 1 - 0.2063$

$\mathbf{P(Y >28) = 0.7937}$

= 79.37%

7 0

4 years ago