Ah for this problem you are thinking quite a bit hard on. The problem is actually simpler than it looks. The problem states that a bike travels at a constant speed of 3.1 m/s for 6 s and asks how far will it go?. To figure this out you simply need to take 3.1 times 6 s because every second the bike travels 3.1 m. So the answer to this problem would be 18.6 m
The answer is 117.6 J
The potential energy of
the object is actually its stored energy:
<span>E =
m · g · h
E - the potential energy of the object,
m - the mass of the object,
g - acceleration due to gravity,
h - the height of the object.
m = 4 kg
g = 9.8 m/s</span>²
h = 3 m
E = 4 * 9.8 * 3 = 117.6 J
Answer:
I = 0.75 A
Explanation:
The question is not to calculate the resistance, but to calculate the current. (The resistance is already given by the value of 2 Ohm).
U = I * R
I = U / R
with U = 1.5 V and R = 2 Ohm
I = 1.5 / 2
I = 0.75 A
bigger acceleration......................
initial velocity is given as 41 km/h at 60 degree North of West
After some time the velocity is given as
now we can find the acceleration
now the distance is given by
so the magnitude of distance is
