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emmainna [20.7K]
3 years ago
6

An astronaut has a mass of 50.0 kg on earth. what is her mass on the moon, where gravity is 1 6 that on earth?

Physics
1 answer:
never [62]3 years ago
6 0

I believe the correct gravity on the moon is 1/6 of Earth. Take note there is a difference between 1 6 and 1/6.

HOWEVER, we should realize that the trick here is that the question asks about the MASS of the astronaut and not his weight. Mass is an inherent property of an object, it is unaffected by external factors such as gravity. What will change as the astronaut moves from Earth to the moon is his weight, which has the formula: weight = mass times gravity.

<span>Therefore if he has a mass of 50 kg on Earth, then he will also have a mass of 50 kg on moon.</span>

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If two objects, like the eggs in the video, experience the same change in momentum but over time periods of
antoniya [11.8K]

Explanation:

what is the force

ican't under stand these question

4 0
2 years ago
A runner wants to run 12.0 km . Her running pace is 8.2 mi/hr . How many minutes must she run? Express your answer using two sig
Hunter-Best [27]

Answer:

53 minutes

Explanation:

To solve this problem, we need to use common proportions to convert.

= 11.7km * 1mi/1.61km * 1hr/8.2mi * 60min/hr

≈ 53 minutes

Best of LUck!

5 0
3 years ago
A puck moves 2.35 m/s in a -22 degree direction. A hockey stick pushes it for 0.215 s, changing its velocity to 6.42 m/s in a 50
Whitepunk [10]

Answer:

Displacement in Y direction is 0.434 m

Explanation:

initial velocity of the puck is 2.35 m/s at -22 degree

so here it is given as

v_i = 2.35 cos22 \hat i - 2.35 sin22 \hat j

v_i = 2.18 \hat i - 0.88 \hat j

final velocity is given as 6.42 m/s at 50 degree

so we have

v_f = 6.42 cos50 \hat i + 6.42 sin50\hat j

v_f = 4.13 \hat i + 4.92\hat j

now displacement in Y direction is given as

\Delta y = \frac{v_f + v_i}{2}t

\Delta y = \frac{-0.88 + 4.92}{2} (0.215)

\Delta y = 0.434 m

5 0
3 years ago
Explain two ways you could reduce the friction between two surfaces
abruzzese [7]
<span>A lubricant such as oil, grease, graphite powder  can reduce the friction between two surfaces. Or using metal balls to space them and reduce the contact surface area as used in ball bearings.</span>
3 0
3 years ago
What are the three longest wavelengths for standing waves on a 264- cm -long string that is fixed at both ends
miv72 [106K]

The three longest wavelengths for the standing waves on a 264-cm long string that is fixed at both ends are:

  1. 5.2 meters.
  2. 2.6 meters.
  3. 1.7meters.

Given data:

Length of the fixed string = 264cms = 2.64 meters

The wavelength for standing waves is given by:

λ = 2L/n

where,

  • λ is the wavelength
  • L is the length of the string

For n = 1,

  • λ = 2×2.6/1

= 5.2 meters

For n = 2,

  • λ = 2×2.6/2

= 2.6 meters

For n = 3,

  • λ = 2×2.6/3

= 1.7 meters

To learn more about standing waves: brainly.com/question/14151246

#SPJ4

7 0
2 years ago
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