2) How much work is required to pull a sled 15<br> meters if you use 30N of force?

The manufacturer of a 6V dry-cell flashlight battery says that the battery will deliver 15 mA for 60 continuous hours. During th

Vaselesa [24]

Answer:

16200 J

Explanation:

t = Time the battery is on = 60 hours

I = Current = $15\times 10^{-3}\ A$

Average voltage

$V=\dfrac{6+4}{2}=5\ V$

Energy is given by

$E=V\times I\times t$

$\\\Rightarrow E=5\times 15\times 10^{-3}\times 60\times 3600$

$\\\Rightarrow E=16200\ J$

The energy delivered in the given time is 16200 J

6 0

2 years ago

PLEASE ANSWER WILL GIVE BRAINLIEST

Karolina [17]

Answer:

B. NET force: 2 resultant motion: left

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C. Net force: 3 Resultant motion: Left

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D. Net Force: 7 Resultant motion: right

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E. Net Force:0 resultant motion: NO MOTION

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F. NET Force: 3 resultant motion: Down

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G. NET FORCE: 10 resultant motion: up

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H. Net force: 3 Resultant motion: left

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I. Net force: 50 Resultant motion: right

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J. NET FORCE: 75 Resultant motion: down

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K. Net force :200 Resultant motion: Right

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L. Net force: 0 resultant motion:No motion

Explanation:

8 0

2 years ago

In the Bohr model of the atom, an electron in an orbit has a fixed ____.

worty [1.4K]

The answer is C. an electron in an orbit has a fixed energy.

3 0

2 years ago

Calculate the potential energy at the top of the giant drop if the car weights 1000 kg

bonufazy [111]

The gravitional potential energy, relative to the bottom of the giant drop, in joules, is (9800) times (the height of the drop in meters). That's the PE of the empty car only, not counting any hapless screaming souls who may be trapped in it at that moment.

6 0

2 years ago

A sailboat is traveling to the right when a gust of wind causes the boat to accelerate leftward at 2.5m/s2 for 4s. After t

Ber [7]

Answer:

+7.0 m/s

Explanation:

Let's take rightward as positive direction.

So in this problem we have:

a = -2.5 m/s^2 acceleration due to the wind (negative because it is leftward)

t = 4 s time interval

v = -3.0 m/s is the final velocity (negative because it is leftward)

We can use the following equation:

v = u + at

Where u is the initial velocity

We want to find u, so if we rearrange the equation we find:

$u = v - at = (-3.0 m/s) - (-2.5 m/s^2)(4 s)=+7.0 m/s$

and the positive sign means the initial direction was rightward.

6 0

3 years ago

2) How much work is required to pull a sled 15 meters if you use 30N of force?