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Oliga [24]
3 years ago
12

The molecular weight of ethanol (CHgCHzOH) is 46 and its density is 0.789 g/cm3. A. \A4rat is the molarity of ethanol in beer th

at is 5% ethanol by volume? [Alcohol content of beer varies from about 4Vo (lite beer) to B% (stout beer).1
Chemistry
1 answer:
mash [69]3 years ago
7 0

Answer:

0.86M

Explanation:

Hello,

In this case, one must consider that the ethanol's concentration in beer is defined as:

\% et =\frac{m_{et}}{m_{beer}}

In such a way, since molarity is defined as:

M=\frac{mol_{et}}{Volume_{solution}}

One is asked to compute the moles, considering a basis of 5 milliliters of ethanol and 100 milliliters of beer, thus:

mol_{et}=5mL*\frac{0.789g}{1mL} *\frac{1mol}{46g}=0.086mol\ et

Now, the volume in molarity is required in liters, therefore:

Volume_{beer}=100mL*\frac{1L}{1000mL}=0.1L

Therefore, the molarity turns out:

M=\frac{0.086mol}{0.1L}=0.86M

Best regards.

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A single covalent bond is made up of​
SIZIF [17.4K]

Answer:

In chemistry, a single bond is a chemical bond between two atoms involving two valence electrons. That is, the atoms share one pair of electrons where the bond forms. Therefore, a single bond is a type of covalent bond.

Explanation:

(copied from Google)

4 0
3 years ago
If 3 moles of a compound use 12 J of energy in a reaction, what is the Hreaction in kJ/mol
igomit [66]

Answer:

\Delta _RH=4x10^{-3}\frac{kJ}{mol}

Explanation:

Hello,

In this case, the molar enthalpy of reaction is obtained by dividing the involved energy by the reacting moles:

\Delta _RH=\frac{12J}{3mol} =4\frac{J}{mol}

Thus, it is important to notice that the compound "uses" the energy, it means that it absorbs the energy, for that reason the sign is positive. Moreover, computing the result in kJ/mol we finally obtain:

\Delta _RH=4\frac{J}{mol}*\frac{1kJ}{1000J} =4x10^{-3}\frac{kJ}{mol}

Best regards.

5 0
3 years ago
The mass of a solid substance is 21.112 g. If the volume of the solid substance is 19.5 cm3, calculate the density of the substa
Ostrovityanka [42]

Answer:

ρ = 1.08 g/cm³

Explanation:

Step 1: Given data

Mass of the substance (m): 21.112 g

Volume of the substance (V): 19.5 cm³

Step 2: Calculate the density of the substance

The density (ρ) of a substance is equal to its mass divided by its volume.

ρ = m / V

ρ = 21.112 g / 19.5 cm³

ρ = 1.08 g/cm³

The density of the substance is 1.08 g/cm³.

6 0
3 years ago
Given the following information, what is the concentration of H2O(g) at equilibrium? [H2S](eq) = 0.671 M [O2](eq) = 0.587 M Kc =
MAVERICK [17]

<u>Answer:</u> The equilibrium concentration of water is 0.597 M

<u>Explanation:</u>

Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_{c}

For a general chemical reaction:

aA+bB\rightleftharpoons cC+dD

The expression for K_{eq} is written as:

K_{c}=\frac{[C]^c[D]^d}{[A]^a[B]^b}

The concentration of pure solids and pure liquids are taken as 1 in the expression.

For the given chemical reaction:

2H_2S(g)+O_2(g)\rightleftharpoons 2S(s)+2H_2O(g)

The expression of K_c for above equation is:

K_c=\frac{[H_2O]^2}{[H_2S]^2\times [O_2]}

We are given:

[H_2S]_{eq}=0.671M

[O_2]_{eq}=0.587M

K_c=1.35

Putting values in above expression, we get:

1.35=\frac{[H_2O]^2}{(0.671)^2\times 0.587}

[H_2O]=\sqrt{(1.35\times 0.671\times 0.671\times 0.587)}=0.597M

Hence, the equilibrium concentration of water is 0.597 M

8 0
3 years ago
If the density of an ideal gas at stp if found to be 0.0902 g/l, what is its molar mass?
lisabon 2012 [21]
P=0.0902 g/l
v=22.4 l/mol   (stp)

M=vp

M=22.4 l/mol * 0.0902 g/l=2.020 g/mol

M=2.020 g/mol
4 0
3 years ago
Read 2 more answers
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