Question

1. (NH)2CrO-

Answer 1

Question:

1. (NH)2CrO

a) Number of moles of H:

b) Number of moles of N:

Answer:

a) Number of moles of H: 2

b) Number of moles of N: 2

Explanation:

The  $(NH)_2CrO$ is ammonium Chromate which is monoclinic and yellow Crystal that is formed due to the reaction of ammonium Hydroxide and ammonium di-chromate. It is used as catalyst, corrosion inhibitor as well as analytical inhibitors.

Question:

2. Ag.SO.

a) Molar Mass:

b) Percent Composition of Ag:

c) Percent Composition of S:

d) Percent Composition of O:​

Answer:

a) Molar Mass:   155.93 Kg

b) Percent Composition of Ag:   69%

c) Percent Composition of S:  20.5%

d) Percent Composition of O:​ 10.2%

Explanation:

Molar mass =   molar mass of Ag +  molar mass of S +  molar mass of O  

=>107.87+32.06+16

=> 155.93 Kg

Percent Composition of Ag

= $\frac{ \text{mass due to Ag}}{\text {total molar mass}} \times 100$

= $\frac{107.87}{155.93} \times 100$

= 0.69 \times 100

= 69%

Percent Composition of S:

= $\frac{ \text{mass due to S}}{\text {total molar mass}} \times 100$

=$\frac{32.06}{155.93} \times 100$

= 0.205 \times 100

= 20.5%

Percent Composition of O:

= $\frac{ \text{mass due to O}}{\text {total molar mass}} \times 100$

= $\frac{16.00}{155.93} \times 100$

= 0.102 \times 100

= 10.2%