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STatiana [176]
3 years ago
7

How did scientists determine the age of the ocean floor

Physics
2 answers:
Umnica [9.8K]3 years ago
6 0

the layers of rocks, the ancient treasures that are at the bottom of the sea, how old the coral is. But I don't think they determined how old it is, how would the dinosaurs that lived in water swim or any drink water. I don't know if this helps but hopefully it does. Also scientist have made advanced tech that could help with the age determination of the ocean floor.


Llana [10]3 years ago
3 0
 Scientists can determine the age of the seafloor thanks to the changing magnetic field of our planet. Every once in a while the currents in the liquid core, which create the Earth's magnetic field, reverse themselves: This is called a geomagnetic reversal. 

hope this helps!
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Can someone please help, ty!
lyudmila [28]

Answer:hypothesis: the plant died of lack  of light,moisture,or water

Explanation:

to test my hypothesis i put a plant in a room at room temp and repeat how i grew it,and observe what went wrong. hope this helps=)

5 0
3 years ago
A car traveling with constant speed travels 150 km in 7200s what is the speed of the car
Oksana_A [137]
Velocity is distance/time 

so 150/7200=.0208km/s 

unless you have to convert it to miles or something else. but use the formula!
5 0
3 years ago
Why do you think we cannot use a common fuel like diesel or gasoline for space travel ?
Ede4ka [16]

Answer:

Explanation:

it take oxygen in the atmosphere to burn it... in space there isn't any air  :0

5 0
2 years ago
A light horizontal spring has a spring constant of 138 N/m. A 3.35 kg block is pressed against one end of the spring, compressin
BARSIC [14]

Answer:

U_k = 0.113

Explanation:

using the law of the conservation of energy:

E_i -E_f=W_f

\frac{1}{2}Kx^2=NU_kd

where K is the spring constant, x is the spring compression, N is the normal force of the block, U_k is the coefficiet of kinetic friction and d is the distance.

Also, by laws of newton, N is calculated by:

N = mg

N = 3.35 kg * 9.81 m/s

N = 32.8635

So, Replacing values on the first equation, we get:

\frac{1}{2}(138)(0.123)^2= (32.8635)U_k(0.281m)

solving for U_k:

U_k = 0.113

8 0
3 years ago
20. Consider a model steel bridge that is 1/100 the exact scale of the real bridge that is to be built. a. If the model bridge w
Veseljchak [2.6K]
The model bridge captures all the structural attributes of the real bridge, at a reduced scale.

Part a.
Note that volume is proportional to the cube of length. Therefore the actual bridge will have 100^3 = 10^6 times the mass of the model bridge.

Because the model bridge weighs 50 N, the real bridge weighs
(50 N)*10^6 = 50 MN.

Part b.
The model bridge matches the structural characteristics of the actual bridge.
Therefore the real bridge will not sag either.
6 0
3 years ago
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