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erastova [34]
3 years ago
14

If you are involved in a collision where there is injury, you must report the incident within .......

Engineering
1 answer:
Misha Larkins [42]3 years ago
4 0

Answer:

24 hours

Explanation:

you must exchange insurance details after a collision if someone is injured. Otherwise you must report the collision to us as soon as possible (and no later than 24 hours). Although you must report such a collision straight away you should always seek medical help in the first instance.

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Π/4 = 1 - 1/3 + 1/5 - 1/7 + 1/9 ...
leva [86]

Answer: Pi= 4 - 4/3 + 4/5 - 4/7 + 4/9 ...

Explanation:

Is the same as the example,

If Π/4 = 1 - 1/3 + 1/5 - 1/7 + 1/9 ...

Then

(Π/4 )*4= 4*(1 - 1/3 + 1/5 - 1/7 + 1/9 ...)

Π =4 - 4/3 + 4/5 - 4/7 + 4/9 ...

The way to write this is

Sum(from n=0 to n=inf) of (-1)^n 4/(2n+1)

(photo)

6 0
4 years ago
The results of a _________ test will determine if there is suitable drainage and the size of the drain field that will be requir
topjm [15]

Answer:

The results of a percolation test will determine if there is suitable drainage and the size of the drain field that will be required for a septic system.

7 0
2 years ago
Explain when it is appropriate to use Tier II?
garik1379 [7]

????? what do u mean tier 2

3 0
3 years ago
Need help fast I been stuck in this for the longest
gavmur [86]

Answer:

3rd and 4rth

Explanation:

a geologist studies the earth and both of these have something to do with the earth

6 0
3 years ago
A motorist is driving his car at 60km/hr when he observes that a traffic light 250m ahead turns red. The traffic light is
Alecsey [184]

Explanation:

Okay soo-

Given-

u = 60 km/hr = 60×1000/3600=50/3 m/s

t = 20 s

s = 250 m

a = ?

v = ?

Solution -

Here, acceleration is uniform.

(a) According to 2nd kinematics equation,

s = ut + ½at^2

250 = 50/3 ×20 + 0.5×a×20×20

250-1000/3=200a

(750-1000)/3=200a

a = -250/(3×200)

a = -5/12

a = 0.4167 m/s^2

The required uniform acceleration of the car is 0.4167 m/s^2.

(b) According to 1st kinematics equation

v = u + at

v = 50/3 + (-5/12)×20

v = 50/3-25/3

v = 25/3

v = 8.33 m/s

The speed of the car as it passes the traffic light is 8.33 m/s.

Good luck!

5 0
2 years ago
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