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Marrrta [24]
2 years ago
15

HELP HURRY‼️‼️‼️ FAST

Chemistry
2 answers:
lesya692 [45]2 years ago
8 0

I believe the answer is D

barxatty [35]2 years ago
5 0
I think its D is the correct one
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What is the minimum of acetic anhydride (102.1 g/mol) required to react completely with the 2.94 grams of salicylic acid? What v
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Answer:

a) the minimun of acetic anhydride required for the  reaction is 2.175 g (CH3CO)2O

b) V acetic anhydride = 2.010 mL

Explanation:

  • balanced reaction:

      C6H4OHCOOH + (CH3CO)2O  ↔  C9H8O4 + C2H4O2

⇒ mol salicylic acid = 2.94 g C6H4OHCOOH * ( mol C6H4OHCOOH / 138.121 g ) = 0.0213 mol C6H4OHCOOH

⇒ mol acetic anhydride = 0.0213 mol C6H4OHCOOH * ( mol (CH3CO)2O /  mol  C6H4OHCOOH ) = 0.0213 mol (CHECO)2O

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b) V = 2.175 g (CH3CO)2 * ( mL / 1.082 g ) = 2.010 mL (CH3CO)2O

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All other units are gotten from them

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Fill in the coefficients that will balance the following reaction:
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