Draw the structural formula of trans-1,3-dimethylcyclohexane in the chair conformation. Choose a chair from the Templates toolba
r at the bottom. Make sure it’s the appropriate chair, including any heteroatoms. Replace the appropriate hydrogens with the appropriate CH3 or other groups. Important: Never delete the hydrogen atoms or bonds in the ring or directly attached to the ring. Also, do not try to move them by drag and drop. These actions will break the chair conformation structures. Just replace them!
1 answer:
Answer:
Look picture
Explanation:
The structural formula of a chemical compound is a graphic representation of the molecular structure, showing how the atoms are possibly arranged in space.
The real structure in what cyclohexane exist is called the chair conformation. This conformation is called the chair because it looks like a reclining lounge chair (Look picture).
The draw of trans-1,3-dimethylcyclohexane is in the chair conformation. The trans position means that one methyl group is in ecuatorial position while the other one is in axial position.
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Answer:
Pressure, P = 67.57 atm
Explanation:
<u>Given the following data;</u>
- Volume = 0.245 L
- Number of moles = 0.467 moles
- Temperature = 159°C
- Ideal gas constant, R = 0.08206 L·atm/mol·K
<u>Conversion:</u>
We would convert the value of the temperature in Celsius to Kelvin.
T = 273 + °C
T = 273 + 159
T = 432 Kelvin
To find the pressure of the gas, we would use the ideal gas law;
PV = nRT
Where;
- P is the pressure.
- V is the volume.
- n is the number of moles of substance.
- R is the ideal gas constant.
- T is the temperature.
Making P the subject of formula, we have;
Substituting into the formula, we have;
<em>Pressure, P = 67.57 atm</em>
Answer:
Answer: (1R,2S) / (1S, 2R) , (1R,2R) / (1S, 2S)
Explanation:
Sodium borohydride reduction of benzoin will give four possible stereo isomers out of which are (1R,2S) - (1S, 2R) isomers and (1R,2R) - (1S, 2S) isomers which are known as enantiomers.
In general enantiomers show single spot in the TLC as they do not show any difference in Rf value (i.e) (1R,2S) - (1S, 2R) isomers show only one spot although they are two compounds and also (1R,2R) - (1S, 2S) isomers also show one spot. That is the reason why you are observing two spots in the TLC ( of reaction mixture) other than starting materilal.
