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nikitadnepr [17]
1 year ago
6

Mark pushes his broken car 140 m down the block to his friend's house. He has to exert a 160 N horizontal force to push the car

at a constant speed.
How much thermal energy is created in the tires and road during this short trip?
Express your answer to two significant figures and include the appropriate units.
Physics
1 answer:
sesenic [268]1 year ago
3 0

The thermal energy used by the tires is 1.14 J.

Here, the thermal energy used will be the work done by Mark.

Given,

Distance = 140 m

Force exerted = 160 N

Thermal energy = ?

We know,

Work = force * displacement

But here the thermal energy of tires is asked.

In this question, the thermal energy used is the energy consumed to do the work.

So, using the formula of work we can find the thermal energy.

W = 160 / 140 = 1.14 J

Therefore the thermal energy used by the tires is 1.14J

To learn more about thermal energy, refer: brainly.com/question/1687193

#SPJ4

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Alex73 [517]
<h3><u>Answer;</u></h3>

Latitude determines the duration of daylight hours.

<h3><u>Explanation;</u></h3>
  • <em><u>The amount of daylight hours depends on the latitude and how Earth orbits the sun. </u></em>
  • <em><u>The tilting of the earth  as it orbits the sun leads to a variation of solar energy that changes with latitude which causes a seasonal variation in the intensity of sunlight reaching the surface and the number of hours of daylight.</u></em>
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3 0
3 years ago
Read 2 more answers
A peregrine falcon is the fastest animal in the world. When it dives, it can accelerate to
svp [43]

The speed of the falcon is 144 km/h

Explanation:

The speed of a body is a scalar quantity telling how fast the object is moving, without giving any information about its direction.

It can be calculated as:

speed = \frac{d}{t}

where

d is the distance covered

t is the time taken

In this problem, the falcon has a speed of

speed = 40 m/s

We want to convert it into km/h. Let's keep in mind that:

1 km = 1000 m

1 h = 3600 s

Therefore, we convert as follows:

speed = 40 \frac{m}{s} \cdot \frac{3600 s/h}{1000 m/k}=144 km/h

Learn more about speed:

brainly.com/question/8893949

#LearnwithBrainly

5 0
3 years ago
You do 1,500j of work in using a hammer. the hammer does 825j of work on a nail. what is the efficiency of the hammer?
KATRIN_1 [288]
A tool or machine's work efficiency is represented by the ratio of the amount of energy exerted and the amount of work done by the object. Thus, if you exert 1500 J work and the hammer does 825 J, the work efficiency is 

Efficiency = \frac{825}{1500} = 0.55
Efficiency = 55%

Thus, the efficiency of the hammer is 55%.

Answer: 55%

 
6 0
3 years ago
What type of forces affects the speed and direction of motion of an object?
aleksley [76]

you are correct it is B those all play a key factor in motion and direction

plz mark brainliest

4 0
2 years ago
(a) Figure 1 shows a mas of 1200 kg hung by a massless cable supported by a counterweight of mass 900 kg. You may assume the gra
Effectus [21]

Answer:

1.43 m/s², 10,300 N

Explanation:

First things first is to draw a picture.  Fortunately, one was already provided.

Next, we need to draw a free body diagram for each mass.

The 1200 kg mass has two forces acting on it: tension pulling up and weight pulling down.

Similarly, the 900 kg mass has two forces acting on it: tension pulling up and weight pulling down.

Now we apply Newton's second law.  Let's start with the 1200 kg.  If we say that up is positive, then:

∑F = ma

T - W = M(-a)

T - Mg = -Ma

Notice that I made the acceleration negative.  That's because we know that the heavier mass will be accelerating down.

Now we apply Newton's second law to the 900 kg mass:

∑F = ma

T - W = ma

T - mg = ma

Now we have two equations and two unknowns (T and a).  Let's solve for the acceleration first.  To do that, let's subtract the two equations so we can eliminate T (if you prefer, you can also use substitution instead):

-mg − (-Mg) = ma − (-Ma)

-mg + Mg = ma + Ma

g (M - m) = a (M + m)

a = g (M - m) / (M + m)

Given that M = 1200 kg, m = 900 kg, and g = 10 m/s²:

a = 10 m/s² (1200 kg - 900 kg) / (1200 kg + 900 kg)

a = 10/7 m/s²

a ≈ 1.43 m/s²

Now let's find the tension by plugging our answer into either of the two equations.

T - mg = ma

T - (900 kg) (10 m/s²) = (900 kg) (10/7 m/s²)

T = 72000/7 N

T ≈ 10,300 N

I'm not sure what rounding rules you need to follow, but hopefully this helps.

3 0
3 years ago
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