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nikitadnepr [17]
1 year ago
6

Mark pushes his broken car 140 m down the block to his friend's house. He has to exert a 160 N horizontal force to push the car

at a constant speed.
How much thermal energy is created in the tires and road during this short trip?
Express your answer to two significant figures and include the appropriate units.
Physics
1 answer:
sesenic [268]1 year ago
3 0

The thermal energy used by the tires is 1.14 J.

Here, the thermal energy used will be the work done by Mark.

Given,

Distance = 140 m

Force exerted = 160 N

Thermal energy = ?

We know,

Work = force * displacement

But here the thermal energy of tires is asked.

In this question, the thermal energy used is the energy consumed to do the work.

So, using the formula of work we can find the thermal energy.

W = 160 / 140 = 1.14 J

Therefore the thermal energy used by the tires is 1.14J

To learn more about thermal energy, refer: brainly.com/question/1687193

#SPJ4

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A planet is discovered orbiting around a star in the galaxy Andromeda at four times the distance from the star as Earth is from
Dmitriy789 [7]

Answer:

Tp/Te = 2

Therefore, the orbital period of the planet is twice that of the earth's orbital period.

Explanation:

The orbital period of a planet around a star can be expressed mathematically as;

T = 2π√(r^3)/(Gm)

Where;

r = radius of orbit

G = gravitational constant

m = mass of the star

Given;

Let R represent radius of earth orbit and r the radius of planet orbit,

Let M represent the mass of sun and m the mass of the star.

r = 4R

m = 16M

For earth;

Te = 2π√(R^3)/(GM)

For planet;

Tp = 2π√(r^3)/(Gm)

Substituting the given values;

Tp = 2π√((4R)^3)/(16GM) = 2π√(64R^3)/(16GM)

Tp = 2π√(4R^3)/(GM)

Tp = 2 × 2π√(R^3)/(GM)

So,

Tp/Te = (2 × 2π√(R^3)/(GM))/( 2π√(R^3)/(GM))

Tp/Te = 2

Therefore, the orbital period of the planet is twice that of the earth's orbital period.

5 0
3 years ago
Read 2 more answers
. A spring has a length of 0.200 m when a 0.300-kg mass hangs from it, and a length of 0.750 m when a 1.95-kg mass hangs from it
kap26 [50]

Answer:

29.4 N/m

0.1  

Explanation:

a) From the restoring Force we know that :  

F_r = —k*x  

the gravitational force :  

F_g=mg  

Where:

F_r is the restoring force .

F_g is the gravitational force

g is the acceleration of gravity

k is the constant force  

xi , x2 are the displacement made by the two masses.

Givens:

<em>m1 = 1.29 kg</em>

<em>m2 = 0.3 kg  </em>

<em>x1   = -0.75 m  </em>

<em>x2 = -0.2 m </em>

<em>g   = 9.8 m/s^2  </em>

Plugging known information to get :

F_r =F_g

-k*x1 + k*x2=m1*g-m2*g

k=29.4 N/m

b) To get the unloaded length 1:  

l=x1-(F_1/k)

Givens:

m1 = 1.95kg , x1 = —0.75m  

Plugging known infromation to get :

l= x1 — (F_1/k)  

= 0.1  

 

3 0
3 years ago
Which is the correct order to use in writing the name of an ionic compound?
muminat

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Fynjy0 [20]

Answer:

16.25 m

Explanation:

we know that the equation pf parabola

y=kx^2

from bellow figure the coordinate of parabola is (600,65) that is y=600 and x=65

putting the the value of y and x in the equation of parabola

65=k600^2

k=0.0001805

now the equation is

y=0.0001805x^2

we have to find the value of y at x=300m

so y=0.0001805\times 300^2

y=16.25 m

4 0
3 years ago
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