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Anastaziya [24]
3 years ago
12

A rigid, insulated tank that is initially evacuated is connected though a valve to a supply line that carries steam at 1 MPa and

300∘C. Now the valve is opened, and steam is allowed to flow slowly into the tank until the pressure reaches 1 MPa, at which point the valve is closed.
Determine the final temperature of the steam in the tank, in ∘C.
Physics
1 answer:
meriva3 years ago
6 0

Answer:

Final Temperature of the steam tank = 456.4°C

Explanation:

Assuming it to be a uniform flow process, kinetic and potential energy to be zero, and work done and heat input to be zero also.  We can conclude that,

Enthalpy of the steam in pipe = Internal Energy of the steam in tank

Using the Property tables and Charts - Steam tables,  

At Pressure= 1 MPa and Temperature= 300°C,

Enthalpy = 3051.2 kJ/kg

At Pressure= 1 MPa and Internal Energy= 3051.2 kJ/kg,

Temperature = 456.4°C.

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Mrac [35]

Answer:

A

Explanation:

since its the tip, you will feel it the most there.

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2 years ago
A spaceship travels at approximately 0. 25c with respect to earth. this means 24 hours at the spaceship will be x hours to us on
Blababa [14]

The time passed on earth is  mathematically given as

t' = 24.79 hrs

<h3>What is the time passed on earth?</h3>

Generally, the equation for is time  mathematically given as

t' = \gamma t

Where

\gamma = Lorentz\ factor \\\\\gamma = 1/ \sqrt {(1 - v^2/c^2)}

t' = t/ \sqrt {(1 - v^2/c^2)}

Therefore

t' = 24/ \sqrt {(1 - (0.25c/c)^2) }

t'= 24/ \sqrt {(1 - 0.25^2)

t' = 24.79 hrs

In conclusion, the time passed on earth

t' = 24.79 hrs

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4 0
1 year ago
An object is released from rest and falls in free fall motion. The speed v of the object after it has fallen a distance y is giv
konstantin123 [22]

Answer:

8.91 %

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Since v² = 2gy

By the relative error formula,

2Δv/v = Δg/g + Δy/y multiplying by 100%, we have

2Δv/v × 100% = Δg/g × 100 % + Δy/y × 100%

2(Δv/v × 100%) = Δg/g × 100 % + Δy/y × 100%

Δg/g × 100 % = 2(Δv/v × 100%) - Δy/y × 100%

Since Δv/v × 100% = 3.69 % and Δy/y × 100% = 5 %

Since we have a difference for the percentage error in g, we square the percentage errors and add them together. So,

[Δg/g × 100 %]² = [2(Δv/v × 100%)]² + [Δy/y × 100%]²

[Δg/g × 100 %]² = [2(3.69)]² + [5%]²

[Δg/g × 100 %]² = [4)(3.69 %)² + [5%]²

[Δg/g × 100 %]² = 54.4644 %² + 25%²

[Δg/g × 100 %]² = 79.4644 %²

taking square-root of both sides, we have

[Δg/g × 100 %] = 8.91 %

So, the percent uncertainty in the calculated value of g is 8.91 %

6 0
3 years ago
An archer pulls her bowstring back 0.376 m by exerting a force that increases uniformly from zero to 251 N. (a) What is the equi
Amanda [17]

Answer:

(A) 667.5 N/m

(B)

Explanation:

(A) Let the spring constant be k.

Using the formula F = kx

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(B)

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8 0
3 years ago
How is work calculated?
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Work is force times distance. If there's no distance, there's no work being done.

6 0
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