Answer:
The length of the trail = 22796 ft
Explanation:
From the ΔABC
AC = length of the trail = x
AB = 6100 - 600 = 5500 ft
Angle of inclination
= 15°



x = 22796 ft
Since x = AC = Length of the trail.
Therefore the length of the trail = 22796 ft
Answer:
c)is unique to that element
Explanation:
The spectrum emitted by a element shows the internal electronic structure of that element.We know that all element is having different internal electronic structure that is why all element emits different spectrum.And the spacing between the spectrum is uneven .
Therefore the answer will be option C.
c)is unique to that element
Answer:
The box displacement after 6 seconds is 66 meters.
Explanation:
Let suppose that velocity given in statement represents the initial velocity of the box and, likewise, the box accelerates at constant rate. Then, the displacement of the object (
), in meters, can be determined by the following expression:
(1)
Where:
- Initial velocity, in meters per second.
- Time, in seconds.
- Acceleration, in meters per square second.
If we know that
,
and
, then the box displacement after 6 seconds is:

The box displacement after 6 seconds is 66 meters.
Answer:
.
Explanation:
The frequency
of a wave is equal to the number of wave cycles that go through a point on its path in unit time (where "unit time" is typically equal to one second.)
The wave in this question travels at a speed of
. In other words, the wave would have traveled
in each second. Consider a point on the path of this wave. If a peak was initially at that point, in one second that peak would be
How many wave cycles can fit into that
? The wavelength of this wave
gives the length of one wave cycle. Therefore:
.
That is: there are
wave cycles in
of this wave.
On the other hand, Because that
of this wave goes through that point in each second, that
wave cycles will go through that point in the same amount of time. Hence, the frequency of this wave would be
Because one wave cycle per second is equivalent to one Hertz, the frequency of this wave can be written as:
.
The calculations above can be expressed with the formula:
,
where
represents the speed of this wave, and
represents the wavelength of this wave.