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3 years ago

Explain how a Faraday motor works, please. Help me out

1 answer:

6 0

The battery makes electrons flow through the circuit, and the electrons move from the copper wire that's hanging down are free to move through the salty water to the aluminum foil. This causes electrons to flow through the wire.

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What are five types of organisms That can reproduce asexually

Sindrei [870]

Answer:

Bacteria, Hydra, Copperheads, Blackworms, and Strawberries

Explanation:

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3 years ago

Write down an example scenario of an object that has acceleration

Grace [21]

Answer:

An object which experiences either a change in the magnitude or the direction of the velocity vector can be said to be accelerating. This explains why an object moving in a circle at constant speed can be said to accelerate - the direction of the velocity changes.

if a car turns a corner at constant speed, it is accelerating because its direction is changing. The quicker you turn, the greater the acceleration. So there is an acceleration when velocity changes either in magnitude (an increase or decrease in speed) or in direction, or both.

Explanation:

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2 years ago

Question 3

pickupchik [31]

When a police officer is trying to decide if a driver is speeding, what is his point of reference. The speed limit

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2 years ago

A total electric charge of 4.00 nC is distributed uniformly over the surface of a metal sphere with a radius of 26.0 cm. The pot

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1 year ago

Water (rhoH20 = 1000.0 kg/m3 ) flows through a garden hose that goes up a step 20.0 cm high. The cross-sectional area of the hos

Soloha48 [4]

Answer:

P₂ = 138.88 10³ Pa

Explanation:

This is a problem of fluid mechanics, we must use the continuity and Bernoulli equation

Let's start by looking for the top speed

Q = A₁ v₁ = A₂ v₂

We will use index 1 for the lower part and index 2 for the upper part, let's look for the speed in the upper part (v2)

v₂ = A₁ / A₂ v₁

They indicate that A₂ = ½ A₁ and give the speed at the bottom (v₁ = 1.20 m/s)

v₂ = 2 1.20

v₂ = 2.40 m / s

Now let's write the Bernoulli equation

P₁ + ½ ρ v₁² + ρ g y₁ = P2 + ½ ρ v₂² + ρ g y₂

Let's clear the pressure at point 2

P₂ = P₁ + ½ ρ (v₁² - v₂²) + ρ g (y₁-y₂)

we put our reference system at the lowest point

y₁ - y₂ = -20 cm

Let's calculate

P₂ = 143 10³ + ½ 1000 (1.20² - 2.40²) + 1000 9.8 (-0.200)

P₂ = 143 103 - 2,160 103 - 1,960 103

P₂ = 138.88 10³ Pa

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3 years ago