Answer:
Δ
Explanation:
Hello,
Butane's combustion is:
Now the change in the Gibbs free energy for this reaction is computed via (don't forget that oxygen's Gibbs free energy of formation is 0 since it is an element):
Δ
4Δ
5Δ
-Δ
Δ
Δ
Now, since the calculation is done for 1 mol of butane, the change in the Gibbs free energy for this fuel is:
Δ
Best regards.
A. zn2 + 2e- --zn(s)
zinc oxide is reduced therefore it's an oxidizing agent
Answer:
Explanation:
You multiply the concentration (in moles per litre) by the volume in litres. The number of moles of a substance in one litre of solution is called its molarity. The official symbol for molarity is “c” (concentration), but most people use the symbol “M”. where n is the number of moles and V is the volume in litres
Answer:
b,d,f
Explanation:your welcome give brainilest
The amount remaining at the end of 5 half-lives is 7.81×10¹³ g
From the question given above, the following data were obtained:
- Half-life (t½) = 5730 years
- Original amount (N₀) = 2.5×10¹⁵ g
- Number of half-lives (n) = 5
- Amount remaining (N) =?
The amount remaining can be obtained as follow:
N = 1/2ⁿ × N₀
N = 1/2⁵ × 2.5×10¹⁵
N = 1/32 × 2.5×10¹⁵
N = 0.03125 × 2.5×10¹⁵
N = 7.81×10¹³ g
Therefore, the amount remaining after 5 half-lives is 7.81×10¹³ g
Learn more about half-life: brainly.com/question/25783920
