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alexgriva [62]
3 years ago
13

How does energy travel in a mechanical wave?

Chemistry
2 answers:
nlexa [21]3 years ago
7 0
I think the answer would be medium
sergejj [24]3 years ago
5 0

Answer:

The Answer is in a medium

Explanation:

I know this because I do, I took the test.

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8. Which type of bond results when one or more valence
Gekata [30.6K]

Answer:

B

Explanation:

8 0
3 years ago
The summary or ending of your experiment​
Katyanochek1 [597]

Answer:

Conclusion

Explanation:

I believe you were asking for the term that best matches with the description given. Typically the conclusion summarizes your experiment in a 1 to 2 paragraph format.

7 0
3 years ago
Calculate the number of moles in a 14.5 gram sample of C4H10.
cricket20 [7]
Moles= mass divided by molar mass
Molar mass= 12.01(4) + 1.01(10)
                 = 58.14g/mol

Moles=14.5g / 58.14g/mol
         =0.249

Therefore there are approx 0.249 moles in a 14.5g sample of C4H10
6 0
2 years ago
I don't know how to solve this​
Misha Larkins [42]

For the first part, use the question M=mol/vol (liters)

To do this, you have the given 1.6 M solution

divide the 360g by the molar mass of ethanol (44.07) to get moles

360/44.07=8.16 mol

so

1.6M = 8.16 mol/x vol

volume: 5.1 Liters

8 0
3 years ago
A chemical engineer must calculate the maximum safe operating temperature of a high-pressure gas reaction vessel. The vessel is
Airida [17]

Answer:

the maximum safe operating temperature the engineer should recommend for this reaction is 616 °C  

Explanation:

Given the data in the question;

First we calculate the Volume of the steel cylinder;

V = πr²h

radius r = Diameter / 2 = 27 cm / 2 = 13.5 cm

height h = 32.4 cm

so we substitute

V = π × ( 13.5 cm )² × 32.4 cm

V  = π × 182.25 cm × 32.4 cm

V = 18550.79 cm³  

V = 18.551 L

given that; maximum safe pressure P = 3.10 MPa = 30.5946 atm

vessel contains 0.218kg or 218 gram of carbon monoxide gas

molar mass of carbon monoxide gas is 28.010 g/mol

so

moles of carbon monoxide gas n = 218 gram /  28.010 g/mol = 7.7829 mol

we know that;

PV = nRT

solve for T

T = PV / nR

we know that gas constant R = 0.0820574 L•atm•mol⁻¹ K⁻¹

so we substitute

T = ( 30.5946 × 18.551 ) / ( 7.7829 × 0.082 )

T = 567.5604 / 0.6381978

T = 889.317387 K

T = ( 889.317387 - 273.15 ) °C

T = 616.167 ≈ 616 °C  { 3 significant digits }

Therefore, the maximum safe operating temperature the engineer should recommend for this reaction is 616 °C  

6 0
2 years ago
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