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3 years ago

Which scientist established the law of octaves ?

Chemistry

2 answers:

quester [9]3 years ago

8 0

Answer:

John Newlands

Explanation:

just did on edgen

goblinko [34]3 years ago

5 0

the answer is D. John Newlands <3

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Consider a situation in which 211 g

Stella [2.4K]

Answer:

3.00 mol

Explanation:

Given data:

Mass of P₄ = 211 g

Mass of oxygen = 240 g

Moles of P₂O₅ = ?

Solution:

Chemical equation:

P₄ + 5O₂ → 2P₂O₅

Number of moles of P₄:

Number of moles = mass/ molar mass

Number of moles = 211 g / 123.88 g/mol

Number of moles = 1.7 mol

Number of moles of O₂ :

Number of moles = mass/ molar mass

Number of moles = 240 g / 32g/mol

Number of moles = 7.5 mol

Now we will compare the moles of product with reactant.

O₂ : P₂O₅

5 : 2

7.5 : 2/5×7.5 = 3.00

P₄ : P₂O₅

1 : 2

1.7 : 2×1.7 = 3.4 mol

Oxygen is limiting reactant so the number of moles of P₂O₅ are 3.00 mol.

Mass of P₂O₅:

Mass = number of moles × molar mass

Mass = 3 mol ×283.9 g/mol

Mass = 852 g

3 0

3 years ago

Help which one will it be

salantis [7]

Answer:

Explanation:

6 0

2 years ago

Read 2 more answers

Calculate the volume of an object that has a density of 4 g/mL and has a mass of 128 grams. Show your work

SOVA2 [1]

The first one is 32mL and the second one is 2.62 and I think it’s grams/mL I’m not for sure about the letters on the second one

4 0

2 years ago

A metal M forms the oxide M2O. When 0.890 grams of M reacts with pure oxygen, 0.956 grams of M2O form. Write the balanced equati

Alla [95]

The molar mass of M is 0.225g/mol and the element M is Hydrogen

If a metal M combines with an oxygen element to form the oxide, $M_2O$ then the chemical reaction will be expressed as:

$4M + O_2 -> 2M_2O\\$

This shows that 4 moles of an unknown element M react with the oxygen element to produce the oxide $M_2O$

Given the following parameters

Mass of M = 0.890 grams

Mass of $M_2O$ = 0.956 grams

Get the molar mass of M:

Molar mass = Mass/number of moles

Molar mass = 0.890/4

Molar mass = 0.225g/mol

Hence the molar mass of M is 0.225g/mol and the element M is Hydrogen

Learn more here: brainly.com/question/6996520

5 0

2 years ago

Read 2 more answers

How many grams of sulfuric acid is needed to neutralize 380 ml of solution with pH = 8.94

erma4kov [3.2K]

Answer : The mass of sulfuric acid needed is $16.23\times 10^{-5}g$ .

Solution : Given,

pH = 8.94

Volume of solution = 380 ml = $380\times 10^{-3}$ $(1ml=10^{-3}L)$

Molar mass of sulfuric acid = 98.079 g/mole

As we know,

$pH+pOH=14\\pOH=14-8.94=5.06$

$pOH=-log[OH^-]$

$5.06=-log[OH^-]$

$[OH^-]=0.00000871=8.71\times 10^{-6}mole/L$

Now we have to calculate the moles of $OH^-$ .

Formula used : $Moles=Concentration\times Volume$

$\text{ Moles of }[OH^-]=\text{ Concentration of }[OH^-]\times Volume\\\text{ Moles of }[OH^-]=(8.71\times 10^{-6}mole/L)\times (380\times 10^{-3}L)=3309.8\times 10^{-9}moles$

For neutralization, equal number of moles of $H^+$ ions will neutralize same number of $OH^-$ ions.

$\text{ Moles of }[OH^-]=\text{ Moles of }[H^+]=3309.8\times 10^{-9}moles$

As, $H_2SO_4\rightarrow 2H^++SO^{2-}_4$

From this reaction, we conclude that

2 moles of $H^+$ ion is given by the 1 mole of $H_2SO_4$

$3309.8\times 10^{-9}$ moles of $H^+$ ion is given by $\frac{3309.8\times 10^{-9}}{2}=1654.9\times 10^{-9}$ moles of $H_2SO_4$

Now we have to calculate the mass of sulfuric acid.

Mass of sulfuric acid = Moles of $H_2SO_4$ × Molar mass of sulfuric acid

Mass of sulfuric acid = $(1654.9\times 10^{-9}moles)\times (98.079g/mole)=162310.94\times 10^{-9}=16.23\times 10^{-5}g$

Therefore, the mass of sulfuric acid needed is $16.23\times 10^{-5}g$ .

3 0

3 years ago