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3 years ago

Which scientist established the law of octaves ?

Chemistry

2 answers:

quester [9]3 years ago

8 0

Answer:

John Newlands

Explanation:

just did on edgen

goblinko [34]3 years ago

5 0

the answer is D. John Newlands <3

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igor_vitrenko [27]

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3 years ago

Why should you clean up after every investigation

8_murik_8 [283]

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3 years ago

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Why does Europe, the USA, and Canada have acid rain?

Gala2k [10]

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3 years ago

Given the following balanced equation, determine the rate of reaction with respect to [Cl2]. If the rate of Cl2 loss is 4.44 × 1

PolarNik [594]

Answer:

8.88 x 10⁻² M/s

Explanation:

The rate of reaction for:

NO(g) + Cl₂ (g) ⇒ 2NOCl(g)

is rate = -ΔNO/Δt = -ΔCl2/Δt = 1/2 ΔNOCl/Δt

so ΔNOCl/Δt = 2 ΔCl2/Δt = 2 x 4.44 × 10⁻² M/s = 8.88 x 10⁻² M/s

In general given a reaction

aA + bB ⇒ cC + dD

rate = -1/a ΔA/Δt = -1/b ΔB/Δt = 1/c ΔC/Δt = 1/d ΔD/Δt

8 0

3 years ago

2) 2KClO3 --> 2KCl + 3O2

aleksandrvk [35]

$2 \text{ KClO}_3 \to 2 \text{ KCl}+3\text{ O}_2$

$2 \text{ mols of KClO}_3 \equiv 3 \text{ mols of O}_2$

$19 \text{ mols of KClO}_3 \equiv 3\cdot 9,5 \text{ mols of O}_2$

$\boxed{19 \text{ mols of KClO}_3 \equiv 28,5 \text{ mols of O}_2}$

$2 \text{ mols of KClO}_3 \equiv 2 \text{ mols of KCl}$

$62 \text{ mol of KClO}_3 \equiv 62 \text{ mol of KCl}$

Using the atomic mass given in the periodic table:

$62\cdot(39+35,5+16\cdot3) \text{ g of KClO}_3 \equiv 62 \text{ mol of KCl}$

$62\cdot122,5 \text{ g of KClO}_3 \equiv 62 \text{ mol of KCl}$

$7595 \text{ g of KClO}_3 \equiv 62 \text{ mol of KCl}$

$\boxed{7,595 \text{ kg of KClO}_3 \equiv 62 \text{ mol of KCl}}$

$2 \text{ KCl}+3\text{ O}_2\to 2 \text{ KClO}_3$

$3 \text{ mols of O}_2 \equiv 2 \text{ mols of KCl}$

Using the atomic mass given in the periodic table:

$3\cdot(2\cdot 16) \text{ g of O}_2 \equiv 2\cdot(39+35,5) \text{ g of KCl}$

$96\text{ g of O}_2 \equiv 149\text{ g of KCl}$

$\dfrac{39}{149}\cdot 96\text{ g of O}_2 \equiv \dfrac{39}{149}\cdot 149\text{ g of KCl}$

$\boxed{25,13\text{ g of O}_2 \equiv 39\text{ g of KCl}}$

This result is an aproximation.

8 0

3 years ago