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3 years ago

Lollll I need help with this question

Chemistry

1 answer:

Drupady [299]3 years ago

6 0

Answer:

Waves are any vibration that transfers energy from place to place.

Explanation:

IM NOT SURE ABOUT THE VIBRATION BIT BUT I AM ABOUT THE ENERGY

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Suppose in an experiment to determine the amount of sodium hypochlorite in bleach, 0.0000524 mol K I O 3 were titrated with an u

11111nata11111 [884]

Answer: The amount of sodium thiosulfate required is $2.62\times 10^{-5}$ moles

Explanation:

Moles of $KIO_3$ solution given = 0.0000524 moles

The chemical equation for the reaction of potassium iodate and sodium thiosulfate follows:

$2KIO_3+Na_2S_2O_3\rightarrow K_2S_2O_3+2NaIO_3$

By Stoichiometry of the reaction:

2 moles of potassium iodate reacts with 1 mole of sodium thiosulfate

So, 0.0000524 moles of potassium iodate will react with = $\frac{1}{2}\times 0.0000524=0.0000262mol$ of sodium thiosulfate

Hence, the amount of sodium thiosulfate required is $2.62\times 10^{-5}$ moles

4 0

3 years ago

n acid with a pKa of 8.0 is present in a solution with a pH of 6.0. What is the ratio of the protonated to the deprotonated form

Nady [450]

Answer : The ratio of the protonated to the deprotonated form of the acid is, 100

Explanation : Given,

$pK_a=8.0$

pH = 6.0

To calculate the ratio of the protonated to the deprotonated form of the acid we are using Henderson Hesselbach equation :

$pH=pK_a+\log \frac{[Salt]}{[Acid]}$

$pH=pK_a+\log \frac{[Deprotonated]}{[Protonated]}$

Now put all the given values in this expression, we get:

$6.0=8.0+\log \frac{[Deprotonated]}{[Protonated]}$

$\frac{[Deprotonated]}{[Protonated]}=0.01$

As per question, the ratio of the protonated to the deprotonated form of the acid will be:

$\frac{[Protonated]}{[Deprotonated]}=100$

Therefore, the ratio of the protonated to the deprotonated form of the acid is, 100

5 0

3 years ago

What would happen if hydrogen and nitrogen combine?

Tanzania [10]

At room temperature and atmospheric pressure, nothing happens when the two gasses are mixed. However, at high temperature and pressure (450C, 200atm), in the presence of an iron oxide catalyst, the production of ammonia is thermodynamically advantageous.

5 0

3 years ago

How many grams of NaOH is needed to neutralize 90 mL of 1.5 N HCl?

AnnZ [28]

mol = conc × v

= 1.5 × 0.09

= 0.135 moles of HCl

HCl + NaOH > NaCl + H2O

1 mole HCl = 1 mole NaOH

0.135 mol HCl = x

x = 0.135 mol NaOH

mass = mol × molar mass

= 0.135 × 40

= 5.4 g

NaOH = 23 + 16 + 1 = 40 g/mol

I'm not a 100% sure if it's correct

6 0

3 years ago

Please answer fast and correct. (15 points)

denis23 [38]

Answer:

the frequency with get lower

6 0

4 years ago

Read 2 more answers