11/10 MgL work has been done by the tension in the string. If the object has been raised a distance l from rest.
<h3>Define work done?</h3>
The definition of work is expanded so that it encompasses both the forces applied to the body and the overall displacement of the body. A constant force F is present before this block. The objective of this force is to move the body d meters in a straight line in the force's direction.
Given,
Mass of object, M
Acceleration of object, a = g/10
Distance covered vertically, L
Tension of string, T
Work done by tension in string, W
W = T × L
By applying equilibrium force on string,
T - Mg = Ma
g = gravitational acceleration
T - Mg = M (g/10)
T = M(g/10) + Mg
T = 11/10 Mg
By substituting the value in, W = T × L
W = 11/10 Mg × L
W = 11/10 MgL
∴ Work done by tension is 11/10 MgL.
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