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Alex
2 years ago
8

2. STEM The mass of an atom of helium is about 4.002 atomic units.

Chemistry
1 answer:
Anit [1.1K]2 years ago
6 0

Answer:

The approximate mass of beryllium is 9.0045 u.

Explanation:

Given data:

mass of helium= 4.002 u

mass of beryllium which is 2.25 times of mass of helium= ?

Solution:

we will multiply the mass of helium with 2.25 times,

4.002 u × 2.25 = 9.0045 u

so the mass of beryllium atom would be 9.0045 u.

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Mass = 25g, Volume = 5mL. What is the density? *
Fantom [35]

Answer:

5ml

Explanation:

m/v

25/5=5

means 25÷5=5

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3 years ago
What is the configuration of all electron pairs arranged around oxygen in a water molecule?
Darina [25.2K]
I think the answer would be : Tetrahedral

Oxygen has 6 electrons and need 2 more electron to complete its octet.  In Tetrahedral, the electrons are arranged so it surround the oxygen and forming a 109 degree bond angel/

hope this helps
4 0
3 years ago
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How many grams of Cl are in 525g of CaCl2
Tema [17]

First we determine the moles CaCl2 present:

525g / (110.9g/mole) = 4.73 moles CaCl2 present 

Based on stoichiometry, there are 2 moles of Cl for every mole of CaCl2:<span>
(2moles Cl / 1mole CaCl2) x 4.73 moles CaCl2 = 9.47 moles Cl </span>

Get the mass:<span>
<span>9.47moles Cl x 35.45g/mole = 335.64 g Cl</span></span>

8 0
3 years ago
Why is a rise in sea level significant?
pogonyaev

Answer:

I honestly dont know but its cool problably from water fill or from the waves going to much

Explanation:

8 0
2 years ago
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What hybridization is required for central atoms that have a tetrahedral arrangement of electron pairs? A trigo- nal planar arra
Reika [66]

Answer:

sp³;

sp²;

sp;

None;

One;

Two;

They're used to pi bonds.

Explanation:

The central atom in a molecule is generally the one that can make a greater number of bonds. The covalent bonds are made by the sharing of electrons, and, for that, the electron must be alone in the orbital.

To explain this, the hybridization theory was created, which states that, the orbitals are joined to form hybrids ones, and so, by the Hund's law, the electrons are alone in them.

The sigma bonds are done in the hybrids orbitals, and at the pure orbitals, the pi bonds are done. The lone pair of electrons are at a pure orbital. So, to know the hybridization of the central atom, we must know how many sigma bonds it does, and it will be the number of hybrids orbitals (each orbital may have two electrons, thus each bond are done in one orbital).

Double bonds and triple bonds have always only one sigma bond, so the number of sigma bonds is equal to the number of bonds, it's not necessary to know if they are simple, double or triple.

When the arrangement is tetrahedral, the central atom does 4 bonds, so it has 4 sigma bonds, and 4 hybrids orbitals (one of s and three for p), does its hybridization is sp³. Because exists only 3 p orbitals, there are no unhybridized p orbitals in this case.

When the arrangement is trigonal, the central atom does 3 bonds, so it has 3 hybrids orbitals (one of s and two of p), thus the hybridization is sp². So there are one unhybridized p orbitals.

When the arrangement is linear, the central atom does 2 bonds, so it has 2 hybrids orbitals (one of s and one of p), thus the hybridization is sp. So, there are two unhybridized p atoms.

As stated before, the unhybridized p orbitals are used to pi bonds.

5 0
3 years ago
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