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vlada-n [284]
3 years ago
7

Give a verbal description of the following absolute value function f(x) = 3 | x - 5 | + 4

Mathematics
1 answer:
lisov135 [29]3 years ago
7 0

Answer:

It is the distance of x from zero. Examples:The absolute value

of 5 is 5.

The absolute value of -10 is 10.

(Complex numbers) The absolute value of 4 + 3 is 5.

Step-by-step explanation:

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Simplify this expression : 2(y+z)
kap26 [50]

Answer:2y + 2z

Step-by-step explanation: you need to multiply the number outside of the parenthesis with the one inside like.

6 0
3 years ago
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Given that triangle LMN has side lengths of 20 inches, 10 inches, and 12 inches, prove triangle LMN is a right triangle. Explain
il63 [147K]

Answer:

It is not a right triangle. The hypotenuse is the biggest side so if you apply the Pythagorean Theorem formula it does not work.

Step-by-step explanation:

A² + B² = C² -------> 10² + 12²=20² --------> 100 + 144 = 400 ---> 244 = 400

8 0
3 years ago
The polynomial equation x^4 + x^3 + x^2 + x + 1 = 0 has zero positive real roots. Please select the best answer from the choices
const2013 [10]

There are zero positive real roots for the given polynomial equation x^4 + x^3 + x^2 + x + 1 = 0. This is explained by Descarte's rule of signs. So, the best choice is T (true).

<h3>What is Descarte's rule of signs?</h3>
  • Descarte's rule of signs tells about the number of positive real roots and negative real roots.
  • The number of changes in signs of the coefficients of the terms of the given polynomial f(x) gives the positive real zeros of the polynomial.
  • The number of changes in signs of the coefficients of the terms of the given polynomial when f(-x) gives the negative real zeros of the polynomial.

<h3>Calculation:</h3>

The given polynomial equation is x^4 + x^3 + x^2 + x + 1 = 0

On applying Descarte's rule of signs,

f(x)=x^4 + x^3 + x^2 + x + 1

Since there are no changes in the signs of the coefficients of any of the terms in the above polynomial, the polynomial has no positive real roots.

f(-x)=(-x)^4+(-x)^3+(-x)^2+(-x)+1\\      = x^4-x^3+x^2-x+1

Since there are four changes in the signs of the coefficients of the terms of the given polynomial when f(-x), the polynomial has 4 negative real roots.

Therefore, the given polynomial equation has zero positive real roots. So, the correct choice is T(true).

Learn more about Descarte's rule of signs here:

brainly.com/question/11590228

#SPJ1

5 0
2 years ago
F(x) = 3(x + 2)2 – 6​
maksim [4K]
F(x)= 3 (x^2 + 4x +4) - 6
= 3x^2 + 12x +12 -6
= 3x^2 + 12x + 6
4 0
3 years ago
ASAP PLEASE
madam [21]

Answer:

he has to pick the phone up 100 more times

6 0
3 years ago
Read 2 more answers
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