Question

Can someone please help me with my maths question​

Answer 1

Answer:

D

Step-by-step explanation:

Since RS is parallel to PQ, gradient of RS is equal to gradient of PQ.

$\boxed{gradient = \frac{y1 - y2}{x1 - x2} }$

Gradient of RS

= gradient of PQ

$= \frac{18 - 10}{ - 9 - ( - 3)}$

$= \frac{8}{ - 9 + 3}$

$= \frac{8}{ - 6}$

$= - \frac{4}{3}$

y- intercept occurs at x= 0. Let the coordinates of the y-intercept of RS be (0, y).

$\frac{y - 6}{0 - 3} = - \frac{4}{3}$

$\frac{y - 6}{ - 3} = - \frac{4}{3}$

Multiply both sides by -3:

y -6= 4

y= 6 +4

y= 10

Thus, the correct option is D.