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mars1129 [50]
3 years ago
12

Cho phản ứng hóa học xảy ra theo phương trình sau: Al + HNO3 ® Al(NO3)3 + N2O + H2O. Sau phản ứng thu được 3,36 (l) khí N2O (đkc

) (sản phẩm khử duy nhất). Tính lượng Al và HNO3 đã phản ứng? (theo 2 cách ).
Chemistry
1 answer:
Amanda [17]3 years ago
3 0

Explanation:

my God what kinda learning you doing?

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A compound consists of only one type of element?
Gnoma [55]

Answer:

A compound can easily be split up into its different elements.

Explanation:

5 0
3 years ago
1 pts
soldier1979 [14.2K]

Answer:

144 g

Explanation:

Use the mole ratio of 4 mol CO2 for every 9 mol O2 to convert from mol O2 to mol CO2. Then use the molar mass of CO2 to convert from mol of CO2 to grams of CO2.

7.34 mol O2 • (4 mol CO2 / 9 mol O2) • (44.01 g CO2 / 1 mol CO2) = 144 g CO2

5 0
3 years ago
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A certain chemical reaction releases of heat for each gram of reactant consumed. How can you calculate what mass of reactant wil
WARRIOR [948]

Answer:

Specific heat capacity formula

Explanation:

The heat capacity gives the exact heat energy at which a given mass of a substance is heated from one temperature to another.

This formula can help determine how much heat is gained or lost during the reaction and is given by:

Q = mcΔT

where:

Q = heat energy in Joules or Calories

m - mass of the substance (g)

c = Specific heat capacity (J/kg°C)

ΔT = change in temperature = (final temp - initial temp) (°C)

I hope this was helpful.

3 0
3 years ago
Hydrogen ion reacts with zinc to produce_____ gas?
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▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓

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6 0
3 years ago
Be sure to answer all parts. Consider both 5-methyl-1,3-cyclopentadiene (A) and 7-methyl-1,3,5-cycloheptatriene (B). Which label
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I don’t have a picture but I can describe it to you.

The hydrogen that is attached at the tertiary position on the heptatriene (at the 7-methyl) would be very acidic, as removal would leave a positive charge that could be moved throughout the ring through resonance. This would mean that the three double bonds would be participating in resonance, and the deprotonated structure would be aromatic, thus making this favorable.

The hydrogen that is attached at the tertiary position on the pentadiene (5-methyl) would NOT be acidic, as removal would cause an antiaromatic structure.

Any other hydrogens would NOT be acidic. Those vinylic to their respective double bonds would seriously destabilize the double bond if removed, and hydrogens attached to the methyl group jutting off the ring have no incentive to leave the carbon.

Hope this helps!
6 0
3 years ago
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