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olya-2409 [2.1K]
3 years ago
9

What is true about: Na+1?

Chemistry
1 answer:
AlexFokin [52]3 years ago
6 0

Hey there!

Na is sodium, which has 11 protons.

The more realistic amount of neutrons for this atom to have is 12. 23 would be the sum of protons and electrons.

The atom has a charge of 1+, so there is one less electron than protons, so

11 - 1 = 10 electrons.

Your answer is d. it has 11 protons, 10 electrons, and 12 neutrons.

Hope this helps!

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Answer:

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\frac{20g P_{4} }{1} * \frac{1 mol P_{4} }{123.9g} * \frac{6 mol H_{2} }{1 mol P_{4} } * \frac{2.02g H_{2} }{1 mol H_{2} } = 1.96g H2

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Calculate the volume, in milliliters, for the following:
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Answer: The volume for 0.850 mol of NaNO_{3} from a NaNO_{3} solution is 1700 mL.

The volume of 30.0 g of LiOH from a 2.70 M LiOH solution is 464 mL.

Explanation:

Molarity is the number of moles of solute present in a liter of solution.

  • As given moles of NaNO_{3} are 0.850 mol and molarity of NaNO_{3} solution is 0.5 M. Hence, its volume is calculated as follows.

Molarity = \frac{no. of moles}{Volume (in L)}\\0.5 M = \frac{0.850 mol}{Volume}\\Volume = 1.7 L (1 L = 1000 mL)\\= 1700 mL

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No. of moles = \frac{mass}{molar mass}\\= \frac{30.0 g}{23.95 g/mol}\\= 1.25 mol

So, volume for LiOH solution is calculated as follows.

Molarity = \frac{no. of moles}{Volume (in L)}\\2.70 M = \frac{1.25}{Volume}\\Volume = 0.464 L (1 L = 1000 mL)\\= 464 mL

Therefore, volume of 30.0 g of LiOH from a 2.70 M LiOH solution is 464 mL.

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