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olga nikolaevna [1]
3 years ago
8

The overall energy involved in the formation of CsCl from Cs(s) and Cl2(g) is −443 kJ mol−1. Given the following information: he

at of sublimation for Cs is +76 kJ mol−1, bond dissociation energy for 12Cl2 is +121 kJ mol−1, Ei1 for Cs is +376 kJ mol−1, and Eea for Cl(g) is 349 kJ mol−1. what is the magnitude of the lattice energy for CsCl?
Chemistry
1 answer:
Alex17521 [72]3 years ago
8 0

Explanation:

It is given that total energy is -443 kJ/mol and formula to calculate the lattice energy is as follows.

       Total energy = heat of sublimation + bond dissociation energies + ionization energy for Cs + EA of Cl^{-} + lattice energy

       -443 kJ/mol = 76 + 121 + 376 - 349 + Lattice energy

   Lattice energy = (-443 - 76 -121 - 376 + 349) kJ

       Lattice energy = -667 kJ

Therefore, we can conclude that -667 kJ is the magnitude of the lattice energy for CsCl.

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The equilibrium constant Kc for the reaction below is 0.00584 at a certain temperature. Br2(g) ⇌ 2Br(g) If the initial concentra
Vinil7 [7]

Answer:

Explanation:

Given that:

The chemical equation for the reaction is:

             Br2(g)    ⇌  2Br(g)

Initially  0.0345M  0.0416M

Q_C = \dfrac{[Br]^2}{[Br_2]} = \dfrac{(0.0416)^2}{(0.0345)}= 0.05016

Q_C =0.05016 >>> K_c(0.00584)

Thus, the given reaction will proceed in the  backward direction

 The I.C.E table is as follows:

                       Br2(g)    ⇌  2Br(g)

I               0.0345                 0.0416

C                 +x                        -2x

E             (0.0345+x)            (0.0416 -2x)

K_c = \dfrac{[Br]^2}{[Br_2]} = \dfrac{(0.0416-2x)^2}{(0.0345+x)} = 0.00584

= 0.00173056 - 0.0832x - 0.0832x + 4x² = 0.00584 (0.0345 +x)

= 0.00173056 - 0.166x + 4x² = 2.0148× 10⁻⁴ + 0.00584x

= 0.00173056 - 2.0148× 10⁻⁴ - 0.166x - 0.00584x + 4x²

= 0.00152908  - 0.17184x + 4x²

Solving by using Quadratic formula

x = 0.03038 or 0.0126

For x = 0.03038

At equilibrium

[Br₂] = (0.0345 + 0.03038) = 0.06488 M

[Br] =  (0.0416 -2(0.03038)) = - 0.01916 M

Since we have a negative value for [Br], we discard the value for x

For x = 0.0126

At equilibrium

[Br₂] = (0.0345 + 0.0126) = 0.0471 M

[Br] =  (0.0416 -2(0.0126)) = 0.0164 M

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3 years ago
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Give the reason for the following; 1. Iodimetric titrations are usually performed in neutral or mildly alkaline (pH 8) to weakly
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Answer:

Explanation:

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hope this helps!
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Answer:

In the n = 3 energy level

Explanation:

There's is no further explanation for this.

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