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3 years ago

A qué llamamos fluido en reposo

Chemistry

2 answers:

Svetach [21]3 years ago

7 0

Answer:

Lo llamas hidrostática

Explanation:

SVETLANKA909090 [29]3 years ago

5 0

Answer:

La hidrostática es la ciencia de los fluidos sin movimiento.

Explanation:

The Hydrostatics is the science of fluids with no motion.

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True or false all countries are legally bound to survey and monitor for disease within their bodies

ra1l [238]

Answer:

False..........

7 0

3 years ago

The combustion of 1 mol ch4 releases 803 kj of energy. how much energy is produced from the combustion of 5.00 mol ch4.

Annette [7]

Answer : The energy produced from the combustion of 5 mole $CH_4$ is $4015KJ$

Solution : Given,

Released energy = 803 KJ

The balanced combustion reaction is,

$CH_4+2O_2\rightarrow CO_2+2H_2O$

As per the question,

1 mole of $CH_4$ releases energy = 803 KJ

5 mole of $CH_4$ produced energy = $\frac{5mole}{1mole}\times 803KJ=4015KJ$

Therefore, the energy produced from the combustion of 5 mole $CH_4$ is $4015KJ$

7 0

4 years ago

Calculate the percent yield if 52.9 g of ethanol reacts to produce 26.7 g of ether.

blagie [28]

Answer:

The % yield is 62.7 %

Explanation:

Step 1: the balanced equation

2CH3CH2OH(l) → CH3CH2OCH2CH3(l) + H2O(l)

Step 2: Data given

mass of ethanol = 52.9 grams

molar mass of ethanol = 46.07 g/mol

mass of ether = 26.7 grams

Molar mass of ether = 74.12 g/mol

Step 3: Calculate moles of ethanol

Number of moles = Mass / molar mass

Moles of ethanol = 52.9 grams / 46.07 g/mol

Moles of ethanol = 1.15 moles

Step 4: Calculate moles of ether

For 2 moles of ethanol consumed, we have 1 mole of ether produced

For 1.15 moles of ethanol consumed, we have 1.15/2 = 0.575 moles of ether produced

Step 5: Calculate mass of ether

Mass = moles * Molar mass

Mass ether = 0.575 moles * 74.12 g/mol = 42.62 grams = theoretical yield

Step 6: Calculate % yield

% yield = (26.7 / 42.62) * 100 = 62.7%

The % yield is 62.7 %

6 0

4 years ago

The acidic ingredient in vinegar is acetic acid. The pH of vinegar is around 2.4, and the molar concentration of acetic acid in

IrinaK [193]

Answer: The value of acid ionization constant $K_a$ for acetic acid is $1.87\times 10^{-5}$

Explanation:

$CH_3COOH\rightarrow H^+CH_3COO^-$

cM 0 0

$c-c\alpha$ $c\alpha$ $c\alpha$

So dissociation constant will be:

$K_a=\frac{(c\alpha)^{2}}{c-c\alpha}$

Give c= 0.85 M and $pH$ = 2.4

$pH=-log[H^+]$

$[H^=}=c\times \alpha=10^{-2.4}=3.98\times 10^{-3}$

$K_a=?$

Putting in the values we get:

$K_a=\frac{(3.98\times 10^{-3})^2}{(0.85-3.98\times 10^{-3})}=1.87\times 10^{-5}$

Thus the value of acid ionization constant $K_a$ for acetic acid is $1.87\times 10^{-5}$

5 0

3 years ago

One atom of an element possesses 80 protons, 80 electrons, and 121 neutrons. Given this information, what is the atomic mass of

IRINA_888 [86]

Answer:

I think the answer is 4) 41

Explanation:

APE= atomic number, proton and the electrons are the same number

MAN= mass = atomic number - neutrons

121 - 80 = 41

i haven't done this in a while so hope this helps :)

3 0

3 years ago