Answer:
![(4.5,-3)\textrm{ and }(0,6)](https://tex.z-dn.net/?f=%284.5%2C-3%29%5Ctextrm%7B%20and%20%7D%280%2C6%29)
Step-by-step explanation:
Given:
![x-6=-\frac{1}{6}y^{2}](https://tex.z-dn.net/?f=x-6%3D-%5Cfrac%7B1%7D%7B6%7Dy%5E%7B2%7D)
![2x+y=6](https://tex.z-dn.net/?f=2x%2By%3D6)
Express
in terms of
and then plug in first equation to solve for
.
![2x+y=6\\2x=6-y\\x=\frac{6-y}{2}](https://tex.z-dn.net/?f=2x%2By%3D6%5C%5C2x%3D6-y%5C%5Cx%3D%5Cfrac%7B6-y%7D%7B2%7D)
Now,
.
Multiply 6 on both sides.
![6(\frac{1}{6}y^{2}+\frac{6-y}{2}-6)=6(0)\\y^{2}+3(6-y)-36=0\\y^{2}+18-3y-36=0\\y^{2}-3y-18=0\\(y-6)(y+3)=0\\y=6\textrm{ or }y=-3](https://tex.z-dn.net/?f=6%28%5Cfrac%7B1%7D%7B6%7Dy%5E%7B2%7D%2B%5Cfrac%7B6-y%7D%7B2%7D-6%29%3D6%280%29%5C%5Cy%5E%7B2%7D%2B3%286-y%29-36%3D0%5C%5Cy%5E%7B2%7D%2B18-3y-36%3D0%5C%5Cy%5E%7B2%7D-3y-18%3D0%5C%5C%28y-6%29%28y%2B3%29%3D0%5C%5Cy%3D6%5Ctextrm%7B%20or%20%7Dy%3D-3)
Now, for ![y=-3,x=\frac{6-(-3)}{2}=\frac{6+3}{2}=\frac{9}{2}=4.5](https://tex.z-dn.net/?f=y%3D-3%2Cx%3D%5Cfrac%7B6-%28-3%29%7D%7B2%7D%3D%5Cfrac%7B6%2B3%7D%7B2%7D%3D%5Cfrac%7B9%7D%7B2%7D%3D4.5)
For,
.
Therefore, the solutions for the system of equations are ![(4.5,-3)\textrm{ and }(0,6)](https://tex.z-dn.net/?f=%284.5%2C-3%29%5Ctextrm%7B%20and%20%7D%280%2C6%29)
Answer:
Step-by-step explanation:
X= 3
Y= -4
Answer:
A
Step-by-step explanation:
Answer:
There is no picture
Step-by-step explanation:
<span>The quotient of 12 and the opposite of 3 is </span>12 / -3