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2 years ago

Please find answer.

Mathematics

2 answers:

TiliK225 [7]2 years ago

7 0

Step-by-step explanation:

you need to use the midpoint formula which is

(x1 + x2 / 2 ; y1 + y2/2)

drek231 [11]2 years ago

3 0

Answer:

(1,-2) for the last time

Step-by-step explanation:

Substitute the values and cancel the common factor in the equation

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16 kilometer an hour

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3 years ago

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Find gradient xe^y + 4 ln y = x² at (1, 1)

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$xe^y+4\ln y=x^2$

Differentiate both sides with respect to x, assuming y = y(x).

$\dfrac{\mathrm d(xe^y+4\ln y)}{\mathrm dx}=\dfrac{\mathrm d(x^2)}{\mathrm dx}$

$\dfrac{\mathrm d(xe^y)}{\mathrm dx}+\dfrac{\mathrm d(4\ln y)}{\mathrm dx}=2x$

$\dfrac{\mathrm d(x)}{\mathrm dx}e^y+x\dfrac{\mathrm d(e^y)}{\mathrm dx}+\dfrac4y\dfrac{\mathrm dy}{\mathrm dx}=2x$

$e^y+xe^y\dfrac{\mathrm dy}{\mathrm dx}+\dfrac4y\dfrac{\mathrm dy}{\mathrm dx}=2x$

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$e^y+\left(xe^y+\dfrac4y\right)\dfrac{\mathrm dy}{\mathrm dx}=2x$

$\left(xe^y+\dfrac4y\right)\dfrac{\mathrm dy}{\mathrm dx}=2x-e^y$

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If y ≠ 0, we can write

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2xy-ye^y}{xye^y+4}$

At the point (1, 1), the derivative is

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3 years ago

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2 years ago

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2 years ago

Bobby knows that the perimeter of the original rectangle is 120 meters. He also knows that the perimeter of the reduced rectangl

Whitepunk [10]

Answer:

24 meters is the width of the original rectangle.

Step-by-step explanation:

Given:

Bobby knows that the perimeter of the original rectangle is 120 meters. He also knows that the perimeter of the reduced rectangle is 30 meters and the reduced rectangle has a length of 9 meters.

Now, to get the width of original rectangle.

The reduced rectangle's perimeter = 30 meters.

The reduced rectangle's length = 9 meters.

Now, we find the width of reduced rectangle by using formula:

Let the width of reduced rectangle be $x.$

$Perimeter=2\times length+2\times width$

$30=2\times 9+2\times x$

$30=18+2x$

Subtracting both sides by 18 we get:

$12=2x$

Dividing both sides by 2 we get:

$6=x\\\\x=6\ meters.$

The width of reduced rectangle = 6 meters.

Now, to get the width of original rectangle:

Let the width of original rectangle be $w.$

As given, the perimeter of the original rectangle = 120 meters.

And, the perimeter of reduced rectangle is 30 meters and its width is 6 meters.

So, 30 is equivalent to 6.

Thus, 120 is equivalent to $w.$

Now, to get the width using cross multiplication method:

$\frac{30}{6}=\frac{120}{w}$

By cross multiplying we get:

$30w=720$

Dividing both sides by 30 we get:

$w=24\ meters.$

The width of original rectangle = 24 meters.

Therefore, 24 meters is the width of the original rectangle.

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2 years ago

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Please find answer. ​

Please find answer.