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wlad13 [49]
2 years ago
6

The college is selling tickets to the basketball ball game for $59.30 each.So far they have made $213,480 in ticket sales . How

many tickets have they sold?
Mathematics
1 answer:
Alex73 [517]2 years ago
3 0

Answer:

<h2>3600</h2>

Step-by-step explanation:

Shift the decimals of both 213480 and 59.3 to the right by 2 decimal places. (This is needed to convert 59.3 to 5930, since long division must divide by a whole number.)

21348000÷5930

Therefore, 213480\div 59.3=3600213480÷59.3=3600.

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5 3/20 = 5.15 <=====
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Solve the equation -2 = 3x/5 + 1
kirill [66]

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4 0
2 years ago
A+b=21 b+c=24 c+d=32 d+e=37 e+f=31 f+g=25 g+a=26 find a,b,c,d,e,f,g,
garri49 [273]

Answer:

a = 12

b = 9

c = 15

d = 17

e = 20

f = 11

g = 14

Step-by-step explanation:

Given that

(a + b) = 21 ...... (1)

(b + c) = 24 ........ (2)

(c + d) = 32 ........ (3)

(d + e) = 37 ........ (4)

(e + f) = 31 .......... (5)

(f + g) = 25 ........ (6)

(g + a) = 26 ......... (7)

Hence, adding all the equations we get, 2(a + b + c + d + e + f + g) = 196

⇒ (a + b + c + d + e + f + g) = 98 ...... (8)

Adding equations (2), (4) and (6), we get (b + c + d + e + f + g) = 86.

Therefore, from equation (8), we get a = 98 - 86 = 12 (Answer)

Adding equations (3), (5), and (7) we get,

a + c + d + e + f + g = 89

Hence, from equation (8), we have b = 98 - 89 = 9 (Answer)

Similarly, adding equations (1), (4), and (6) we get,

a + b + d + e + f + g = 83,

Hence, c = 98 - 83 = 15 (Answer)

Now, adding equations (2), (5) and (7), we get

a + b + c + e + f + g = 81. Hence, d = 98 -81 = 17 (Answer)

Adding equations (1), (3), and (6)

a + b + c + d + f + g = 78. Hence e = 98 - 78 = 20 (Answer)

Adding equations (2), (4), and (7)

a + b + c + d + e + g = 87. Hence f = 98 - 87 = 11 (Answer)

Adding equations (1), (3), and (5)

a + b + c + d + e + f = 84. Hence g = 98 - 84 = 14 (Answer)

6 0
3 years ago
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