Question

Prove that……………….xjejj jrf

Answer 1

Answer:

see explanation

Step-by-step explanation:

Using the rules of exponents

$a^{-m}$ = $\frac{1}{a^{m} }$

$a^{\frac{m}{n} }$ = $\sqrt[n]{a^{m} }$

Given

$y^{-\frac{a}{b} }$

= $\frac{1}{y^{\frac{a}{b} } }$

= $\frac{1}{\sqrt[b]{y^{a} } }$