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kykrilka [37]
3 years ago
7

Write on the discovery of electricity not less than a page​

Physics
1 answer:
Veronika [31]3 years ago
8 0

Cevabı bilmiyom arkadaşım benn türküm puan almak için cevap veriyorum hadi bbyy

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How does the momentum of a fast object compare to that of a slow object if they both have the same mass?
Varvara68 [4.7K]
The momentum of a fast object compared to that of a slow object even if they both have the same mass, is their velocities.

Having same mass but different velocities results in different momentum.

Example: mass = 10kg
Velocity 1 = 50 Velocity 2 = 100
Momentum 1 = 10×50 = 500 Ns
Momentum 2 = 10×100 = 1000 Ns

Hope it helped!
3 0
3 years ago
The smallest shift you can reliably measure on the screen is about 0.2 grid units. This shift corresponds to the precision of po
creativ13 [48]

Answer:

The distance is  d = 1.5 *10^{15} \ km

Explanation:

From the question we are told that

        The smallest shift is d = 0.2 \ grid \ units

Generally a grid unit is  \frac{1}{10} of  an arcsec

  This implies that  0.2 grid unit is  k =  \frac{0.2}{10} = 0.02  \  arc sec

The maximum distance at which a star can be located and still have a measurable parallax is mathematically represented as

           d =  \frac{1}{k}

substituting values

           d =  \frac{1}{0.02}

           d = 50 \ parsec

Note  1 \ parsec  \ \to 3.26 \ light \ year \ \to 3.086*10^{13} \ km

So  d = 50 * 3.08 *10^{13}

     d = 1.5 *10^{15} \ km

3 0
3 years ago
Which of the following is the most likely global climate change?a.a decrease in the overall temperature of the Earthb.an increas
andrew11 [14]
I believe the answer is C. an increase in the number of cold climates
5 0
3 years ago
Read 2 more answers
What is the quantity of heat energy required to convert 10g cube of ice at -30oC to steam at 120oC. also draw a graph of tempera
julia-pushkina [17]

30,869.2 J

Explanation:

Given parameters:

Mass of ice cube = 10g

Initial temperature = -30°C

Final temperature = 120°C

Specific heat capacity of water = 4.2J/g°C

Specific heat capacity of ice = 2.1J/g°C

Specific heat capacity of steam  = 1.996J/g°C

Latent heat of fusion of water(l) = 334J/g

Latent heat of vaporization = 2230J/g

Unknown:

Quantity of heat required = ?

Temperature-energy graph = ?

Solution:

The temperature energy profile is attached to this solution.

q = mc∅ₓ + mlₓ + mc∅ₙ + mlₙ + mc∅ₐ

qₓ = mc∅ₓ in converting ice from -30°C to ice at 0°C

qₓ is the amount of heat supplied to the ice that changes its temperature from -30°C to that at freezing point:

qₓ  = 10 x 4.2 x (0-(-30)) = 10 x 2.1 x 30 = 630J

qₓ = mlₓ in converting ice to water

qₓ here is the latent heat used to break the ice bonds without a change in temperature:

qₓ = ml = 10 x 334 = 3340J

qₙ = mc∅ₙ is the heat from water at 0°C to boiling point.

This is the heat required to take water from freezing temperature to its boiling point

qₙ = mc∅ₙ  = 10 x 4.2 x (100 - 0) = 4200J

qₙ  = mlₙ is the heat in vaporizing water

In vaporizing water, there is no temperature change when the hydrogen bonds are broken. The heat supplied is not used to raise temperature. We use the latent heat of vaporization:

qₙ   = 10 x 2230 = 22300J

qₐ = mc∅ₐ from vapor at 100°C to 120°C

This is the heat used to raise the temperature of vapor:

qₐ = 10 x 1.996 x (120-100) = 399.2J

The total heat:

  q = qₓ + qₙ + qₐ = 630J + 3340J + 4200J + 22300J + 399.2J =30,869.2 J

Learn more:

Specific heat brainly.com/question/7210400

#learnwithBrainly

7 0
3 years ago
A heat engine extracts 42. 53 kj from the hot reservior and exhausts 17. 69 kj into the cold reservior. what is the work done?
ludmilkaskok [199]

The answer is  24.84kJ.

We apply the expression for the work done by the heat engine is,

W=E_{i n}-E_{o u t}. Putting all given values in the equation we get the final answer.

What is heat engine?

  • A heat engine is a machine that uses heat to generate power. It draws heat from a reservoir, uses that heat to produce work, such as move a piston or lift weights, and then releases that heat energy into the sink.
  • We are given:The heat input is $E_{i n}=42.53 \mathrm{~kJ}$. The heat output is $E_{o u t}=17.69 \mathrm{~kJ}$.
  • The expression for the work done by the heat engine is,W=E_{i n}-E_{o u t}
  • Substituting the given values in the above expression, we will getW =42.53 \mathrm{~kJ}-17.69 \mathrm{~kJ}=24.84kJ.
  • Thus, the work done by the heat engine is 24.84kJ.

To learn more about heat engine visit: brainly.com/question/15735984

#SPJ4

6 0
2 years ago
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