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3 years ago

Need help for school please

Mathematics

1 answer:

marta [7]3 years ago

7 0

Answer:

Step-by-step explanation:

First, we find the area of each individual polygon:

Starting with C for the half circle:

$C=\pi r^2\\C=\pi (3)^2\\C= 20\\$

Since it's a half circle, we divide the final product by 2:

$C=20/2\\C=10$

Next, the trapezoid:

$A=\frac{a+b}{2} h\\A=\frac{13+6}{2} (8)\\A=76$

Last, since we combined the triangle with the trapezoid, we add all the areas we've found to find the area of the entire shape:

$76+10= 86$

<em>Hope this helped! Have a good day.</em>

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In triangle STU, u2 = s2 + t2. Triangle STU has sides s, t, u opposite to the corresponding vertices S, T, U Which equation is t

wlad13 [49]

Answer:
<span>The measure of angle SUT is equal to 90 degrees
</span>
Explanation:
The Pythagorean theorem states that:
"In any right-angled triangle, the square of the hypotenuse is equal to the sum of squares of the other two sides"
In other words:
(hypotenuse)² = (first side)² + (second side)²

Now, for the given, we have:
u² = s² + t²
This means that the given triangle UST is a right-angled triangle and that side "u" is its hypotenuse.

According to the given, the angle opposite to side "u" is angle U. This means that angle U is the right-angle in this triangle.

Based on the above:
angle U = 90°
angle S + angle T = 180 - 90 = 90°

Now, comparing our deductions to the given choices, we can conclude that the correct choice is:
The measure of angle SUT is equal to 90 degrees

Hope this helps :)

6 0

4 years ago

Read 2 more answers

Suppose the population of rats double every 4 days. If a house began with 4 rats on day 1, how many rats will there be after 4 m

tatuchka [14]

120 days in 4 months start day 1 with 4 rats every 4 days 4 rats add on so what I did is this.

Day 1= 4 rats day 4=8 day 8 = 12 so on intell u hit 118 days.but the answer to your question is.. there will be 114 rats if the population of rats double every 4 days for 4 months. hope this is correct and helps. :)

3 0

3 years ago

Question 2: show working out

kherson [118]

Answer in fraction form is exactly 2/27
Answer in decimal form is approximately 0.07407

========================================================

Explanation:

4 people play both,9 play flat flute only, 12 play piano only.
So 4+9+12 = 13+12 = 25 people play one instrument only or they play both.

We have 27 people total meaning that 27-25 = 2 play neither instrument.

Divide the values 2 and 27 to get
2/27 = 0.07407
this value is approximate (rounded to five decimal places)

5 0

3 years ago

A rectangular prism measuring 8cm and 10cm along the base and 2cm tall

Elden [556K]

If you are asking for the volume than it's 160 squared cm

7 0

3 years ago

Find thd <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdx%7D" id="TexFormula1" title="\frac{dy}{dx}" alt="\frac{dy}{dx}" a

NARA [144]

$x^3y^2+\sin(x\ln y)+e^{xy}=0$

Differentiate both sides, treating $y$ as a function of $x$ . Let's take it one term at a time.

Power, product and chain rules:

$\dfrac{\mathrm d(x^3y^2)}{\mathrm dx}=\dfrac{\mathrm d(x^3)}{\mathrm dx}y^2+x^3\dfrac{\mathrm d(y^2)}{\mathrm dx}$

$=3x^2y^2+x^3(2y)\dfrac{\mathrm dy}{\mathrm dx}$

$=3x^2y^2+6x^3y\dfrac{\mathrm dy}{\mathrm dx}$

Product and chain rules:

$\dfrac{\mathrm d(\sin(x\ln y)}{\mathrm dx}=\cos(x\ln y)\dfrac{\mathrm d(x\ln y)}{\mathrm dx}$

$=\cos(x\ln y)\left(\dfrac{\mathrm d(x)}{\mathrm dx}\ln y+x\dfrac{\mathrm d(\ln y)}{\mathrm dx}\right)$

$=\cos(x\ln y)\left(\ln y+\dfrac1y\dfrac{\mathrm dy}{\mathrm dx}\right)$

$=\cos(x\ln y)\ln y+\dfrac{\cos(x\ln y)}y\dfrac{\mathrm dy}{\mathrm dx}$

Product and chain rules:

$\dfrac{\mathrm d(e^{xy})}{\mathrm dx}=e^{xy}\dfrac{\mathrm d(xy)}{\mathrm dx}$

$=e^{xy}\left(\dfrac{\mathrm d(x)}{\mathrm dx}y+x\dfrac{\mathrm d(y)}{\mathrm dx}\right)$

$=e^{xy}\left(y+x\dfrac{\mathrm dy}{\mathrm dx}\right)$

$=ye^{xy}+xe^{xy}\dfrac{\mathrm dy}{\mathrm dx}$

The derivative of 0 is, of course, 0. So we have, upon differentiating everything,

$3x^2y^2+6x^3y\dfrac{\mathrm dy}{\mathrm dx}+\cos(x\ln y)\ln y+\dfrac{\cos(x\ln y)}y\dfrac{\mathrm dy}{\mathrm dx}+ye^{xy}+xe^{xy}\dfrac{\mathrm dy}{\mathrm dx}=0$

Isolate the derivative, and solve for it:

$\left(6x^3y+\dfrac{\cos(x\ln y)}y+xe^{xy}\right)\dfrac{\mathrm dy}{\mathrm dx}=-\left(3x^2y^2+\cos(x\ln y)\ln y-ye^{xy}\right)$

$\dfrac{\mathrm dy}{\mathrm dx}=-\dfrac{3x^2y^2+\cos(x\ln y)\ln y-ye^{xy}}{6x^3y+\frac{\cos(x\ln y)}y+xe^{xy}}$

(See comment below; all the 6s should be 2s)

We can simplify this a bit by multiplying the numerator and denominator by $y$ to get rid of that fraction in the denominator.

$\dfrac{\mathrm dy}{\mathrm dx}=-\dfrac{3x^2y^3+y\cos(x\ln y)\ln y-y^2e^{xy}}{6x^3y^2+\cos(x\ln y)+xye^{xy}}$

3 0

3 years ago