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vodomira [7]
3 years ago
7

Which race do you guys think I am (btw which picture should I post on insta?)

Chemistry
2 answers:
drek231 [11]3 years ago
6 0

Answer:

hispanic/latina

Explanation:

nataly862011 [7]3 years ago
3 0

I feel like your latina

Explanation:

your eyes and hair are brown and you like like one

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Write the chemical formula of tetraphosphours octasulfide
ArbitrLikvidat [17]

Answer:

P4 S8

Explanation:

8 0
3 years ago
Based on the Phase Change Graph below, what is the Melting Point for this point<br> substance?
Marina CMI [18]

Answer:

Where is the phase melting graph? Can't seem to find it

4 0
3 years ago
Which pathway is correct? proteins to RNA to DNA, DNA to RNA to proteins , RNA to DNA to proteins or DNA to proteins to RNA
Annette [7]

Answer:

The sequence order should be DNA to RNA to Proteins.

Explanation:

For you to get the RNA sequence, you need to find a match for the DNA sequence. Your RNA sequence should only have either AUCG for your 4 nucleotide bases. Once you have the RNA sequence found by pairing it with the DNA sequence, you would then to do use an RNA codon chart to find the amino acids. These amino acids are basically your proteins.

3 0
3 years ago
Read 2 more answers
Suppose you have 250g of gold(I) Chloride. How many grams of Gold do you have?
solniwko [45]

29.26 gram

Explanation:

No of molecules = no of mole × Avogadro's number

No of molecules = mass in gram/ molar mass × Avogadros number

Mass in gram =No of molecules×molar mass / Avogadros number

Mass in gram = 3.012 ×10^23 × 58.5/6.02×10^23

29.26 gram

4 0
3 years ago
Arsenic(III) sulfide sublimes readily, even below its melting point of 320 °C. The molecules of the vapor phase are found to eff
dezoksy [38]

The molecular formula : As₄S₆

<h3>Further explanation</h3>

Given

Rate of effusion of arsenic(III) sulfide = 0.28 times the rate of effusion of Ar atoms

Required

The molecular formula

Solution

Graham's law: the rate of effusion of a gas is inversely proportional to the square root of its molar masses or  

the effusion rates of two gases = the square root of the inverse of their molar masses:  

\rm \dfrac{r_1}{r_2}=\sqrt{\dfrac{M_2}{M_1} }

or  

\rm M_1\times r_1^2=M_2\times r_2^2

Input the value :

1 = Arsenic(III) sulfide

2 = Ar

MM Ar = 40 g/mol

0.28 = √(40/M₁)

M₁=40 : 0.28²

M₁=510 g/mol

The empirical formula of arsenic(III) sulfide =  As₂S₃

(Empirical formula)n = molecular formula

( As₂S₃)n = 510 g/mol

(246.02 g/mol)n = 510 g/mol

n = 2

So the molecular formula : As₄S₆

5 0
3 years ago
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