Question 8 helpppppp
2 answers:
<h2>Hey There!</h2><h2>_____________________________________</h2><h2>Answer:</h2><h2><u>LE CHATELIER PRINCIPLE</u>:</h2>
Le Chatelier's principle is a principle which predicts the effect of change in condition on a the position of a equilibrium.
Change could be in Temperature, Moles(Concentration), Pressure.
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<h2>EFFECTS ON EQUILIBRIUM</h2><h3 /><h3>__________________________________________________</h3><h3>Temperature: </h3>We could change the temperature by increasing or decreasing it, and there are two types of reactions, endothermic or exothermic, both have different outcomes by changing the condition.
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In Endothermic,
When we increase the temperature, It will favor the formation of product thus MORE PRODUCT will be formed - equilibrium will shift towards right i.e. product side.
When we decrease the temperature, It will favor the formation of reactants thus MORE reactant will be formed - equilibrium will shift towards left i.e. reactants side.
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In Exothermic,
When we increase the temperature, It will favor the formation of reactants thus MORE REACTANT will be formed - equilibrium will shift towards left i.e. reactants side.
When we decrease the temperature, It will favor the formation of product thus MORE PRODUCT will be formed - equilibrium will shift towards the right i.e. product side
<h2>_____________________________________</h2><h3>Pressure:</h3>When we increase the pressure, The equilibrium shifts towards the fewer moles of a gas. Wherever there are less moles, it could be any, reactant or product, the increase of Pressure will favor in formation of them.
When we decrease the pressure, The equilibrium shifts towards the more moles of a gas. So whether reactants or product have the higher moles, the decrease in pressure will favor in the formation of them.
<h2>_____________________________________</h2><h3>Concentration of moles:</h3>When we increase the concentration of moles of any substance, The equilibrium will shift away from that substance. So if we want to make more product and there are more moles of reactant present, then Increase the concentration of reactants.
When we decrease the concentration of any substance, The equilibrium will shift towards that substance. So if we want to make more product, decrease its concentration or add more reactant.
<h2>_____________________________________</h2><h3>Catalyst:</h3>By the use of the catalyst, There is no effect on the equilibrium. The rate of both forward and backward reaction are increased with the equal amount.
<h2>_____________________________________</h2><h2>Question:</h2>By keeping that in mind,
A) Extra will shift the equilibrium towards left i.e. more reactants will be formed.
B) Extra N2 is removed, the equilibrium will shift towards the left i.e. more reactants will be formed.
C) N2 is added, the equilibrium will shift towards right i.e. more PRODUCT will be formed. (I assumed there was a typing error and it meant Addition instead of removal)
D) When we decrease the pressure the equilibrium will shift towards the left i.e. more reactant will be formed.
E) Catalyst has no effect on the system
<h2>_____________________________________</h2><h2>Best Regards</h2><h2>'Borz'</h2><h2 />You might be interested in
Answer:
1) 0,081 ft/s
2) 0,746 lb/s
Explanation:
The relation between flow and velocity of a fluid is given by:
Q=Av
where:
- Q, flow [ft3/s]
- A, cross section of the pipe [ft2]
- v, velocity of the fluid [ft/s]
1)
To convert our data to appropiate units, we use the following convertion factors:
1 ft=12 inches
1 ft3=7,48 gallons
1 minute=60 seconds
So,
As the pipe has a circular section, we use A=πd^2/4:
Finally:
Q=vA......................v=Q/A
2)
The following formula is used to calculate the specific gravity of a material:
SG = ρ / ρW
where:
- SG = specific gravity,
- ρ = density of the material [lb/ft3]
- ρW = density of water [lb/ft3] = 62.4 lbs/ft3
then:
ρ = SG*ρW = 1,49* 62,4 lb/ft3 = 93 lb/ft3
To calculate the mass flow, we just use the density of the chloroform in lb/ft3 to relate mass and volume: