Answer:
When one desires to remove debris from the garden then a soil sifter can be used as a beneficial tool. Based on the needs, it can be of different kinds. A landscaper may sift soil that they use at the time of constructing gardens due to many reasons:
1. The soil becomes aerated, and thus, turn soft and easy to work upon.
2. Sifting the soil makes the work of withdrawing undesired substances from the soil easy.
3. It helps the plants to grow much better as the roots possess the tendency to penetrate more easily through the soil.
4. The soil becomes healthy due to shifting, thus, helps in producing a beautiful and healthy landscape.
The 3rd option
because i’m always right:)
Answer:
Se =[Ar] 3d¹⁰ 4s² 4p⁴
Explanation:
The noble gas notation is used for the shortest electronic configuration of other periodic table elements.
For example:
The atomic number of Argon is 18, and its electronic configuration is,
Ar₁₈ = 1s² 2s² 2p⁶ 3s² 3p⁶
The atomic number of selenium is 34, its electronic configuration is,
Se₃₄ = 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁴
By using the noble gas notation, electronic configuration of selenium can be written is shortest form.
Se =[Ar] 3d¹⁰ 4s² 4p⁴
This electronic configuration is also called abbreviated electronic configuration.
Answer:
they're losing electrolytes
Explanation:
When athletes sweat, they're losing electrolytes primarily in the form of sodium (Na+) and chloride (Cl-), so when you start to replace lost fluids, ahtletes should replace the electrolytes as well. Potassium (K+), Magnesium (Mg2+) and Calcium (Ca2+) are electrolytes also lost through sweating.
Answer:
pH = 5.24
Explanation:
Mixture of acetic acid with acetate ion is a buffer (Mixture of a weak acid with its conjugate base). The pH of a buffer can be determined using Henderson-Hasselbalch equation:
pH = pKa + log₁₀ [A⁻] / [HA]
<em>Where pKa is -log Ka = 4.74; [A⁻] is the concentration of conjugate base (Acetate ion) and [HA] is molar concentration of the weak acid.</em>
Concentration of the acetic acid in the 100mL≡0.1L (76mL + 24mL) solution is:
[HA] = 0.024L ₓ (1mol / L) / 0.1L = 0.24M
[A⁻] = 0.076L ₓ (1mol / L) / 0.1L = 0.76M
Replacing in H-H equation:
pH = 4.74 + log₁₀ [0.76M] / [0.24M]
<h3>pH = 5.24</h3>
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