Answer:
6L
Explanation:
<em>if it's 3L per 200kPa</em>
then it would be;
4L per 300kPa
5L per 400kPa
6L per 500kPa
that's how i'd work it out in my head, hope it helps, but not sure though!
Answer:
It is called the atomic theory I believe.
Explanation:
Answer : 0.0392 grams of Zn metal would be required to completely reduced the vanadium.
Explanation :
Let us rewrite the given equations again.



On adding above equations, we get the following combined equation.

We have 12.1 mL of 0.033 M solution of VO₂⁺.
Let us find the moles of VO₂⁺ from this information.

From the combined equation, we can see that the mole ratio of VO₂⁺ to Zn is 2:3.
Let us use this as a conversion factor to find the moles of Zn.

Let us convert the moles of Zn to grams of Zn using molar mass of Zn.
Molar mass of Zn is 65.38 g/mol.

We need 0.0392 grams of Zn metal to completely reduce vanadium.
Answer:
300 kg
Explanation:
The give parameters obtained from a similar question are;
The mass of oseltamivir per capsule = 75 mg
The mass of oseltamivir required, <em>M</em>, is given as follows;
M = The mass of oseltamivir per capsule × The mass taken per person per day × 5 days × The number of people in the city
M = 0.75 mg/capsule × 2 capsule/(day·person) × 5 days × 400,000 people
M = 300,000,000 mg = 300 kg