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FrozenT [24]
2 years ago
6

Is the largest of Saturn's moons, Charon, larger than Mercury?​

Chemistry
1 answer:
vazorg [7]2 years ago
4 0

Answer:

no, Charon is significantly smaller than Mercury

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1
Otrada [13]

Answer:

A. the iron atoms are gaining kinetic energy

Explanation:

when the iron melted and solidifies it loses potential energy and changes to kinetic energy

3 0
3 years ago
Consider the most common ions formed by fluorine (F–), sodium (Na+), magnesium (Mg2+), and aluminum (Al3+), respectively. How ma
alukav5142 [94]

The ions F⁻, Na⁺, Mg²⁺, and Al³⁺ have 10 electrons, as Ne, the closest noble gas.

To determine the number of electrons of an ion, we need to consider:

  • The atomic number (Z): It establishes the number of protons and electrons in the neutral species.
  • The charge: It indicates the number of electrons gained (negative charge) or lost (positive charge).

  • Fluorine (F⁻)

F has 9 electrons (Z = 9) and it gains 1 electron to form F⁻. The total number of electrons is 9 + 1 = 10.

  • Sodium (Na⁺)

Na has 11 electrons (Z = 11) and it loses 1 electron to form Na⁺. The total number of electrons is 11 - 1 = 10.

  • Magnesium (Mg²⁺)

Mg has 12 electrons (Z = 12) and it loses 2 electrons to form Mg²⁺. The total number of electrons is 12 - 2 = 10.

  • Aluminum (Al³⁺)

Al has 13 electrons (Z = 13) and it loses 3 electrons to form Al³⁺. The total number of electrons is 13 - 3 = 10.

The ions F⁻, Na⁺, Mg²⁺, and Al³⁺ have 10 electrons, as Ne, the closest noble gas.

Learn more about ions here: brainly.com/question/3110170

5 0
3 years ago
The volume of 1 mole of o2 gas at T=273k P=1atm is?
svet-max [94.6K]
This is a fact question. At STP, 1 mole of any gas is equal to 22.4 Liters answer is C note: this is STP because Temperature is 273 and pressure is 1 atm
6 0
4 years ago
Read 2 more answers
What is the charge that results when fluorine becomes an ion?
Luden [163]
-1 is the charge that results.
8 0
4 years ago
How many liters of 15.0 molar NaOH stock solution will be needed to make 17.5 liters of a 1.4 molar NaOH solution? Show the work
strojnjashka [21]
2.0 L
The key to any dilution calculation is the dilution factor

The dilution factor essentially tells you how concentrated the stock solution was compared with the diluted solution.

In your case, the dilution must take you from a concentrated hydrochloric acid solution of 18.5 M to a diluted solution of 1.5 M, so the dilution factor must be equal to

DF=18.5M1.5M=12.333

So, in order to decrease the concentration of the stock solution by a factor of 12.333, you must increase its volume by a factor of 12.333by adding water.

The volume of the stock solution needed for this dilution will be

DF=VdilutedVstock⇒Vstock=VdilutedDF

Plug in your values to find

Vstock=25.0 L12.333=2.0 L−−−−−

The answer is rounded to two sig figs, the number of significant figures you have for the concentration od the diluted solution.

So, to make 25.0 L of 1.5 M hydrochloric acid solution, take 2.0 L of 18.5 M hydrochloric acid solution and dilute it to a final volume of 25.0 L.

IMPORTANT NOTE! Do not forget that you must always add concentrated acid to water and not the other way around!

In this case, you're working with very concentrated hydrochloric acid, so it would be best to keep the stock solution and the water needed for the dilution in an ice bath before the dilution.

Also, it would be best to perform the dilution in several steps using smaller doses of stock solution. Don't forget to stir as you're adding the acid!

So, to dilute your solution, take several steps to add the concentrated acid solution to enough water to ensure that the final is as close to 25.0 L as possible. If you're still a couple of milliliters short of the target volume, finish the dilution by adding water.

Always remember

Water to concentrated acid →.NO!

Concentrated acid to water →.YES!
8 0
4 years ago
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