Answer:
7
Explanation:
A quotient is the answer to a division.For example,the quotient of 10 is 2 and 5 because 5÷10=2.
Answer:
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Answer:
The total energy of the motor of the electric vehicle is 1.902 × 10⁸ joules.
Explanation:
Power is the rate of change of work in time, since given input is average power, the total energy (
) of the motor of the electric vehicle, measured in joules, is determined by this formula:

Where:
- Average power, measured in watts.
- Time, measured in seconds.
Now, let convert average power and time into watts and seconds, respectively:
Average Power


Time


Then, the total energy is:


The total energy of the motor of the electric vehicle is 1.902 × 10⁸ joules.
Answer:
heat transfer rate is -15.71 kW
Explanation:
given data
Initial pressure = 4 bar
Final pressure = 12 bar
volumetric flow rate = 4 m³ / min
work input to the compressor = 60 kJ per kg
solution
we use here super hated table for 4 bar and 20 degree temperature and 12 bar and 80 degree is
h1 = 262.96 kJ/kg
v1 = 0.05397 m³/kg
h2 = 310.24 kJ/kg
and here mass balance equation will be
m1 = m2
and mass flow equation is express as
m1 =
.......................1
m1 =
m1 = 1.2353 kg/s
and here energy balance equation is express as
0 = Qcv - Wcv + m × [ ( h1-h2) +
+ g (z1-z2) ] ....................2
so here Qcv will be
Qcv = m × [
] ......................3
put here value and we get
Qcv = 1.2353 × [ {-60}+ (310.24-262.96) ]
Qcv = -15.7130 kW
so here heat transfer rate is -15.71 kW
Answer:
The average loss for this device is $10.90
Explanation:
Given data
Specification = 24 +/- 0.4 Amps
average quality cost = $32.00
average value y = 23.9
standard deviation s = 0.211 Amps
32 = k(24.4 - 24)²
32 = k(0.4)² = k(0.16)
k = 32/0.16 = 200
To evaluate average loss, use
L = k{s² + (y - T)²}
T = 24A
L = 200{0.211² + (23.9 - 24)²}
L = $10.90
The average loss for this device is $10.90