Answer:
w = 0.626 rad / s, v = 3.13 m/s
Explanation:
For this exercise let's use Newton's second law
F = m a
Where the force is a friction force and the acceleration is centripetal,
a = v² / r = w² r
The formula for friction force
fr = μ N
In a free body diagram
N- W = 0
W = N
The frictiμon outside goes from zero to the maximum value, let's calculate the speed for the maximum value of the friction force, replace
μ m g = m w² r
w = √ μ g / r
Let's calculate
w = √(0.2 9.8 / 5)
w = 0.626 rad / s
angular and linear velocity are related
v = w r
v = 0.626 5
v = 3.13 m/s
Explanation:
all I know is every number that have a bar on is equal to one
Absolute positions — latitudes and longitudes
Relative positions — azimuths, bearings, and elevation angles
Spherical distances between point locations
Answer: Shift work communication.
Explanation:
Shift work communication is a type of communication that exist between shift workers, or people at different time zones.
Shift work consists of a three eight hours shift within 24 hours.
Keeping up with a shift work communication requires planning, time management and commitment. It also requires using various communication channels.
Answer:
Explanation:
The determination of any further properties requires the knowledge of two independent properties. (Temperature and specific volume in this case). The specific volumes for saturated liquid and vapor at 140 °C are, respectively:
Since 
, it is a liquid-vapor mixture. The quality of the mixture is:
The specific enthalpies for saturated liquid and vapor at 140 °C are, respectively:
The specific enthalpy is:
