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3 years ago

What forces are acting on a book sitting on a table? Are action-reaction forces involved in this situation?

Chemistry

1 answer:

saw5 [17]3 years ago

3 0

Answer:

Gravitational force
Normal force

Explanation:

These act as the action-reaction forces.

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Write a net ionic equation for the neutralization reaction of acid with a hydroxide base. (Include phase symbols)

zubka84 [21]

Answer:

salt + water. It is called the ionic equation for neutralisation. the acid to form a salt solution.

Explanation:

So what you end up with is you always end up H+ plus OH- yields H2O, because HCl, and NaOH, since they're strong, they fully dissociate. So the Na+, and the Cl - are spectator ions. So with a strong acid and strong base, the net ion equation is always H+ plus OH- yields H2O.

7 0

3 years ago

Copper has a density of 8.920 g/cm3. What mass of copper will occupy 45cm3? What volume of copper will have a mass of 1.0 kg?

mixas84 [53]

Density = mass/volume
so rearranged mass = volume x density
mass = 8.920 x 45 = 401.4g

rearrange (there are 1000grams in 1kg)
volume = mass/density
volume = 1000/8.920
volume = 112.1076233cm3

5 0

4 years ago

Why are noble gases called noble gases?

Colt1911 [192]

Answer:

comes from a translation of the German word Edelgas, which means noble gas.

Why Are Noble Gases Called Noble? The term “noble gas” comes from a translation of the German word Edelgas, which means noble gas. German chemist Hugo Erdmann coined the phrase in 1898. Like a nobleman might consider it undignified to associate with commoners, noble gases tend not to react with other elements.

Explanation:

hope it helps

6 0

3 years ago

If 1.00 mol of argon is placed in a 0.500-L container at 27.0 degree C , what is the difference between the ideal pressure (as p

ElenaW [278]

Answer:

2.0 atm is the difference between the ideal pressure and the real pressure.

Explanation:

If 1.00 mole of argon is placed in a 0.500-L container at 27.0 °C

Moles of argon = n = 1.00 mol

Volume of the container,V = 0.500 L

Ideal pressure of the gas = P

Temperature of the gas,T = 27 °C = 300.15 K[/tex]

Using ideal gas equation:

$PV=nRT$

$P=\frac{1.00 mol\times 0.0821 L atm/mol K\times 300.15 K}{0.500 L}=49.28 atm$

Vander wall's of equation of gases:

The real pressure of the gas= $p_v$

For argon:

$a=1.345 L^2 atm/mol^2$

b=0.03219 L/mol.

$(p_v+(\frac{an^2}{V^2})(V-nb)=nRT$

$(p_v+(\frac{(1.345 L^2 atm/mol^2)\times (1.00 mol)^2}{(0.500 L)^2})(0.500 L-1.00 mol\times 0.03219L/mol)=1.00 mol\times 0.0821 L atm/mol K\times 300.15 K$