Vectors include magnitude & direction so the third option is the correct answer :)
It is a good idea because when mercury heats up, the molecules spread farther apart. Therefore, making them look to have expanded. Thermometers that are digital use a sensor to, as you would say feel the temperature around it.
<u>Answer:</u> The mass of oxygen reacted is ![1.60\times 10^{3}g](https://tex.z-dn.net/?f=1.60%5Ctimes%2010%5E%7B3%7Dg)
<u>Explanation:</u>
We are given:
Moles of propane = 9.98 mol
For the given chemical equation:
![C_3H_8(g)+5O2(g)\rightarrow 3CO_2(g)+4H_2O(g)](https://tex.z-dn.net/?f=C_3H_8%28g%29%2B5O2%28g%29%5Crightarrow%203CO_2%28g%29%2B4H_2O%28g%29)
By Stoichiometry of the reaction:
1 mole of propane reacts with 5 moles of oxygen.
So, 9.98 moles of propane will react with =
of oxygen.
To calculate the mass of carbon dioxide, we use the equation:
![\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20moles%7D%3D%5Cfrac%7B%5Ctext%7BGiven%20mass%7D%7D%7B%5Ctext%7BMolar%20mass%7D%7D)
Moles of oxygen = 49.9 moles
Molar mass of oxygen gas = 32 g/mol
Putting values in above equation:
![49.9mol=\frac{\text{Mass of oxygen}}{32g/mol}\\\\\text{Mass of oxygen}=(49.9mol\times 32g/mol)=1596.8g=1.60\times 10^{3}g](https://tex.z-dn.net/?f=49.9mol%3D%5Cfrac%7B%5Ctext%7BMass%20of%20oxygen%7D%7D%7B32g%2Fmol%7D%5C%5C%5C%5C%5Ctext%7BMass%20of%20oxygen%7D%3D%2849.9mol%5Ctimes%2032g%2Fmol%29%3D1596.8g%3D1.60%5Ctimes%2010%5E%7B3%7Dg)
Hence, the mass of oxygen reacted is ![1.60\times 10^{3}g](https://tex.z-dn.net/?f=1.60%5Ctimes%2010%5E%7B3%7Dg)
Huh I don’t understand but I think c or d
Well a question to ask would be if the mass of the material has changed significantly as that would determine that the substance is radioactive or if there have been any high readings found by a Geiger meter in certain period of time
hope that helps