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malfutka [58]
3 years ago
9

PLEASE HELP ME WITH THIS IF UR GOOD AT PHYSICS!!! 100 POINTS!!!!

Physics
2 answers:
Bingel [31]3 years ago
8 0

#1

  • 0.0009

3zeros hence significant figures will be 4

#2

\\ \sf\longmapsto 31.2+38.02+45

\\ \sf\longmapsto 114.22lbs

#3

\\ \sf\longmapsto 11.5s\pm 0.19s

  • Round it up

\\ \sf\longmapsto 11.5s\pm 0.20s

#4

0.0125%

marta [7]3 years ago
4 0

Answer:

I do apologize but I can't figure out Q 2 , 3 but

Q 1 is 1

Q4 is 0.0125%

so sorry

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cestrela7 [59]

Answer:

B.) a stretched rubber band

Explanation:

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3 years ago
The Heat required to raise the temp. of 20 g water from 25 C to 36 C
Dennis_Churaev [7]
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An unknown object is placed inside of a spherical container and dropped from an airplane. When empty, the spherical container ha
hichkok12 [17]

Answer:

The mass of unknown object is 8.62Kg

Explanation:

To develop this problem it is necessary to apply the equations related to the Drag force and the Force of Gravity.

For the given point, that is, the moment at which the terminal velocity is reached, the two forces equalize, that is,

F_D =F_g

By definition we know that the Drag force is defined as

F_D= \frac{1}{2} C_d \rho A V^2

Where,

C_d = Drag coefficient

\rho =Density

A =Cross-sectional Area

V = Velocity

In the other hand we have,

F_g = (m_1 +m_2) g

Where,

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Equating the two equations we have to

(m_1 +m_2) g=\frac{1}{2} C_d \rho A V^2

Re-arrange for m_2,

m_2 = \frac{1}{2g} C_d \rho A V^2 -m_1

Our values are given by,

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m_1 = 3Kg

d= 32.7*10^{-2}m

r = 16.35*10^{-2}m

Replacing in the equation we have,

m_2 = \frac{1}{2(9.8)}(0.5) (1.22) (\pi*(16.35*10^{-2})^2)*66.7^2 -3

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4 0
3 years ago
Red light of wavelength 651 nm produces photoelectrons from a certain photoemissive material. Green light of wavelength 521 nm p
Mnenie [13.5K]

Answer:

material work function is 0.956 eV

Explanation:

given data

red wavelength 651 nm

green wavelength 521 nm

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to find out

material work function

solution

we know by Einstein photo electric equation  that is

for red light

h ( c / λr ) = Ф +  kinetic energy

for green light

h ( c / λg ) = Ф +  1.50 × kinetic energy

now from both equation put kinetic energy from red to green

h ( c / λg ) = Ф +  1.50 × (h ( c / λr ) - Ф)

Ф =( hc / 0.50) × ( 1.50/ λr  - 1/ λg)

put all value

Ф =( 6.63 ×10^{-34} (3 ×10^{8} )  / 0.50) × ( 1.50/ λr  - 1/ λg)

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4 0
3 years ago
Read 2 more answers
What is the relationship between thickness of lens and focal length?​
Ymorist [56]

Thick lens will have shorter and consequently thin lens will have greater focal length. Because, For a thick lens, the optical path length of the light is more, than for a thin lens, thus, the bending of light will be more in case of a thicker lens. Consequently, it has a shorter focal length.

7 0
3 years ago
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