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3 years ago

PLEASE HELP ME WITH THIS IF UR GOOD AT PHYSICS!!! 100 POINTS!!!!

Physics

2 answers:

Bingel [31]3 years ago

8 0

0.0009

3zeros hence significant figures will be 4

$\\ \sf\longmapsto 31.2+38.02+45$

$\\ \sf\longmapsto 114.22lbs$

$\\ \sf\longmapsto 11.5s\pm 0.19s$

Round it up

$\\ \sf\longmapsto 11.5s\pm 0.20s$

0.0125%

marta [7]3 years ago

4 0

Answer:

I do apologize but I can't figure out Q 2 , 3 but

Q 1 is 1

Q4 is 0.0125%

so sorry

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B.) a stretched rubber band

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An unknown object is placed inside of a spherical container and dropped from an airplane. When empty, the spherical container ha

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Answer:

The mass of unknown object is 8.62Kg

Explanation:

To develop this problem it is necessary to apply the equations related to the Drag force and the Force of Gravity.

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$F_D =F_g$

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Where,

$C_d =$ Drag coefficient

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V = Velocity

In the other hand we have,

$F_g = (m_1 +m_2) g$

Where,

$m_1 =$ Mass of sphere

$m_2 =$ Mass of unknown object

Equating the two equations we have to

$(m_1 +m_2) g=\frac{1}{2} C_d \rho A V^2$

Re-arrange for m_2,

$m_2 = \frac{1}{2g} C_d \rho A V^2 -m_1$

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$C_d = 0.5$

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$m_1 = 3Kg$

$d= 32.7*10^{-2}m$

$r = 16.35*10^{-2}m$

Replacing in the equation we have,

$m_2 = \frac{1}{2(9.8)}(0.5) (1.22) (\pi*(16.35*10^{-2})^2)*66.7^2 -3$

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4 0

3 years ago

Red light of wavelength 651 nm produces photoelectrons from a certain photoemissive material. Green light of wavelength 521 nm p

Mnenie [13.5K]

Answer:

material work function is 0.956 eV

Explanation:

given data

red wavelength 651 nm

green wavelength 521 nm

photo electrons = 1.50 × maximum kinetic energy

to find out

material work function

solution

we know by Einstein photo electric equation that is

for red light

h ( c / λr ) = Ф + kinetic energy

for green light

h ( c / λg ) = Ф + 1.50 × kinetic energy

now from both equation put kinetic energy from red to green

h ( c / λg ) = Ф + 1.50 × (h ( c / λr ) - Ф)

Ф =( hc / 0.50) × ( 1.50/ λr - 1/ λg)

put all value

Ф =( 6.63 × $10^{-34}$ (3 × $10^{8}$ ) / 0.50) × ( 1.50/ λr - 1/ λg)

Ф =( 6.63 × $10^{-34}$ (3 × $10^{8}$ ) / 0.50 ) × ( 1.50/ 651× $10^{-9}$ - 1/ 521 × $10^{-9}$ )

Ф = 1.5305 × $10^{-19}$ J × ( 1ev / 1.6 × $10^{-19}$ J )

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3 years ago

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