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TiliK225 [7]
3 years ago
8

The blank is the core of an atom​

Physics
1 answer:
alexdok [17]3 years ago
5 0

Answer:

The <u>nucleus</u> is the core of an atom.

Step-by-step explanation:

That's just how it is.

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An unknown mass of each substance, initially at 25.0 ∘C, absorbs 1920 J of heat. The final temperature is recorded. Find the mas
zhannawk [14.2K]

Answer: mass for Pyrex glass 84.21g

mass for sand 61.6g

mass for ethanol 41.32g

mass for water 62.07g

Explanation

By definition specific heat is the amount of heat required to change the temperature of 1 kg mas by 1°C

Q=mcΔT is formula for specific heat

Q is heat transfer

m is mass

ΔT is change in temperature

c   is specific heat

c of Pyrex glass= 0.75 j/g°C

c of sand = 0.84 j/g°C

c of ethanol= 2.42 j/g°C

c of water = 4.18 j/g°C

now we will make M(mass) the subject, so equation becomes

m=Q/cΔT

for

pyrex glass T<em>f=</em>55.4°C

m=1920/(55.4-25)*0.75

m=84.21g {after cutting J(joules) and °C we are left with g(grams)}

for

sand T<em>f</em>=62.1°C

m=1920/(62.1-25)*0.84

m=61.6g {after cutting J(joules) and °C we are left with g(grams)}

for

ethanol T<em>f</em>=44.2°C

m=1920/(44.2-25)*2.42

m=41.32g  {after cutting J(joules) and °C we are left with g(grams)}

for

water T<em>f=</em>32.4°

m=1920/(32.4-25)*4.18

m=62.07g  {after cutting J(joules) and °C we are left with g(grams)}

i hope you understand the solution, thank you.

7 0
3 years ago
car company wants to build a wind- powered car that converts 100 percent of the mechanical energy in the wind to the mechanical
navik [9.2K]

EVEN IF they can build such a machine, it's not too useful.

-- If the wind starts and stops, your car would do the same thing.

-- If the wind isn't blowing at all, your car is going nowhere. (and fast)

-- You could never move along the road faster than the wind is moving along the road.

-- You could never move in the direction towards where the wind is coming from.  This has been proven before, with the technological marvel known as the "sailboat".

Call your broker immediately.  Tell him you do NOT want to buy any stock in CarCompany.

3 0
3 years ago
Read 2 more answers
Astrology is considered which of the following types of science?
Murljashka [212]
The answer is A. Astrology is pseudoscience because it is not scientifically backed.
5 0
4 years ago
Read 2 more answers
The compound limestone (which is mined in Crossville) is chemically
Salsk061 [2.6K]

Answer:

True

Explanation:

Limestone is a carbonate chemical sedimentary rock often chemically called calcium carbonate.

The mineral calcium carbonate makes up the framework of this rock that has become the staple material used for cement production.

Chemically, the formula is given as CaCO₃. The rock accumulates from the a rich deposit of calcite, which is the mineral that is made up of calcium carbonate to form the limestone.

          CaCO₃         -        Calcite      -        Limestone

     compound                mineral                   rock

Limestone is a rock and the compound it is made up of is calcium carbonate. In some cases, a Ca-Mg carbonate occurs with limestone and it is called a dolomite.

5 0
4 years ago
A two-liter bottle of your favorite beverage has just been removed from the trunk of your car. The temperature of the beverage i
Ksivusya [100]

Answer:

a) 209.3 kilojoules must be removed from two liter of beverage, b) A rate of heat removal of 1.163 kilowatts is required to cool down 10 2-liter bottles, c) Cooling 10 2-L bottles during 30 minutes costs 4.9 cents.

Explanation:

a) <em>How much heat energy must be removed from your two liters of beverage?</em>

At first we suppose that the beverage has the mass and specific heat of water and that there are no energy interactions between the bottle and its surroundings.

From the First Law of Thermodynamics and definition of sensible heat, we get that amount of removed heat (Q), measured in kilojoules, is represented by the following formula:

Q = \rho \cdot V\cdot c\cdot (T_{o}-T_{f}) (Eq. 1)

Where:

\rho - Density of the beverage, measured in kilograms per cubic meter.

V - Volume of the bottle, measured in cubic meters.

c - Specific heat of water, measured in kilojoules per kilogram-Celsius.

T_{o}, T_{f} - Initial and final temperatures, measured in Celsius.

If we know that \rho = 1000\,\frac{kg}{m^{3}}, V = 2\times 10^{-3}\,m^{3}, c = 4.186\,\frac{kJ}{kg\cdot ^{\circ}C}, T_{o} = 35\,^{\circ}C and T_{f} = 10\,^{\circ}C, then:

Q = \left(1000\,\frac{kg}{m^{3}}\right)\cdot (2\times 10^{-3}\,m^{3})\cdot \left(4.186\,\frac{kJ}{kg\cdot ^{\circ}C} \right) \cdot (35\,^{\circ}C-10\,^{\circ}C)

Q = 209.3\,kJ

209.3 kilojoules must be removed from two liter of beverage.

b) <em>You are having a party and need to cool 10 of these two-liter bottles in one-half hour. What rate of heat removal, in kW, is required?</em>

The total amount of heat that must be removed from 10 2-L bottles is:

Q_{T} = 10\cdot (209.3\,kJ)

Q_{T} = 2093\,kJ

If we suppose that bottles are cooled at constant rate, then, rate of heat removal is determined by this formula:

\dot Q = \frac{Q_{T}}{\Delta t} (Eq. 2)

Where:

Q_{T} - Total heat, measured in kilojoules.

\Delta t - Time, measured in seconds.

\dot Q - Rate of heat removal, measured in kilowatts.

If we know that Q_{T} = 2093\,kJ and \Delta t = 1800\,s, we find that rate of heat removal is:

\dot Q = \frac{2093\,kJ}{1800\,s}

\dot Q = 1.163\,kW

A rate of heat removal of 1.163 kilowatts is required to cool down 10 2-liter bottles.

c) <em>Assuming that your refrigerator can accomplish this and that electricity costs 8.5 cents per kW-hr, how much will it cost to cool these 10 bottles (in $)?</em>

A kilowatt-hour equals 3600 kilojoules. The electricity cost is equal to the  removal heat of 10 bottles (Q_{T}), measured in kilojoules, and unit electricity cost (c), measured in US dollars per kilowatt-hour. That is:

C = c\cdot Q_{T}

If we know that c = 0.085\,\frac{USD}{kWh} and Q_{T} = 2093\,kJ, the total cost of cooling 10 bottles is:

C = \left(0.085\,\frac{USD}{kWh}\right)\cdot \left(2093\,kJ\right)\cdot \left(\frac{1}{3600}\,\frac{kWh}{kJ}  \right)

C = 0.049\,USD

Cooling 10 2-L bottles during 30 minutes costs 4.9 cents.

3 0
4 years ago
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