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2 years ago

The blank is the core of an atom

Physics

1 answer:

alexdok [17]2 years ago

5 0

Answer:

The <u>nucleus</u> is the core of an atom.

Step-by-step explanation:

That's just how it is.

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A sealed container holding 0.0255 L of an ideal gas at 0.981 atm and 65 ∘ C is placed into a refrigerator and cooled to 41 ∘ C w

user100 [1]

Answer:

0.911 atm

Explanation:

In this problem, there is no change in volume of the gas, since the container is sealed.

Therefore, we can apply Gay-Lussac's law, which states that:

"For a fixed mass of an ideal gas kept at constant volume, the pressure of the gas is proportional to its absolute temperature"

Mathematically:

$p\propto T$

where

p is the gas pressure

T is the absolute temperature

For a gas undergoing a transformation, the law can be rewritten as:

$\frac{p_1}{T_1}=\frac{p_2}{T_2}$

where in this problem:

$p_1=0.981 atm$ is the initial pressure of the gas

$T_1=65^{\circ}+273=338 K$ is the initial absolute temperature of the gas

$T_2=41^{\circ}+273=314 K$ is the final temperature of the gas

Solving for p2, we find the final pressure of the gas:

$p_2=\frac{p_1 T_2}{T_1}=\frac{(0.981)(314)}{338}=0.911 atm$

3 0

3 years ago

What is the energy of an electromagnetic wave that has a frequency of

sukhopar [10]

Answer:

$Energy, \; E = 2.6504 * 10^{-34} \; Joules$

Explanation:

Given the following data;

Frequency = 4.0 x 10⁹ Hz

Planck's constant, h = 6.626 x 10-34 J·s.

To find the energy of the electromagnetic wave;

Mathematically, the energy of an electromagnetic wave is given by the formula;

E = hf

Where;

E is the energy possessed by a wave.

h represents Planck's constant.

f is the frequency of a wave.

Substituting the values into the formula, we have;

$Energy, \; E = 4.0 x 10^{9} * 6.626 x 10^{-34}$

$Energy, \; E = 2.6504 * 10^{-34} \; Joules$

8 0

2 years ago

gAn optical engineer needs to ensure that the bright fringes from a double-slit are 15.7 mm apart on a detector that is from the

igomit [66]

Answer:

d = 68.5 x 10⁻⁶ m = 68.5 μm

Explanation:

The complete question is as follows:

An optical engineer needs to ensure that the bright fringes from a double-slit are 15.7 mm apart on a detector that is 1.70m from the slits. If the slits are illuminated with coherent light of wavelength 633 nm, how far apart should the slits be?

The answer can be given by using the formula derived from Young's Double Slit Experiment:

$y = \frac{\lambda L}{d}\\\\d =\frac{\lambda L}{y}\\\\$

where,

d = slit separation = ?

λ = wavelength = 633 nm = 6.33 x 10⁻⁷ m

L = distance from screen (detector) = 1.7 m

y = distance between bright fringes = 15.7 mm = 0.0157 m

Therefore,

$d = \frac{(6.33\ x\ 10^{-7}\ m)(1.7\ m)}{0.0157\ m}\\\\$

7 0

3 years ago

Two waves travel through ocean, one with wavelength 3 m, one with 6 m. Which one has greater speed?

spin [16.1K]

Answer: 6m

Explanation: 6 is more than 3 and their both being measured by m

4 0

2 years ago

What is something I could represent chloroplasts in a project

IgorC [24]

Nulceus - recipe book/instruction manual
Mitochondria - Battery
Endoplasmic reticulum - Printer or a pen?
Golgi aparatus - an envelope
Chloroplasts - green rechargable battery
Cell membrane (elastic band (2 to represent the phospholipid bilayer)
Ribosomes - I guess maybe an ink pot as its the material thats used to write
Cell Wall - the paper bag
lysosomes - washing up liquid (breaks down wate food on a dirty plate)
vaculoes - bottle of water

3 0

2 years ago

The blank is the core of an atom​

The blank is the core of an atom