Answer:
2: p x 3
Step-by-step explanation:
Answer:
-3q
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
5q + -8q
<u>Step 2: Simplify</u>
- Rewrite: 5q - 8q
- Combine like terms: -3q
Hello there! Thank you for asking your question here at Brainly! I will be assisting you with answering this question, and will be teaching you how to handle it on your own in the future.
We have 350 total keychains, in which 10% are yellow, 3/5 are green, and x are red. We will be solving for red, but we need to subtract 10% and 3/5 from 350.
So, let's find out how much 10% of 350 is.
Since 10% is equivalent to 1/10, we can divide 350 by 10 to find how many yellow key chains there are.
350 / 10 = 35.
There are 35 yellow key chains. We can subtract this from 350 to narrow it down.
350 - 35 = 315.
Now, let's find how much 3/5 of 350 is, and subtract it from our new number (315).
Divide 350 by 5, and then multiply that quotient by 3.
350 / 5 = 70.
70 x 3 = 210.
We have 210 green key chains. Now let's subtract that from 315. This will give us the remaining key chains - which are red.
315 - 210 = 105.
There are 105 red key chains.
I hope this helps!
Answer:
x=135°
Step-by-step explanation:
45°- 180°=135x
Answer:
the time taken for the radioactive element to decay to 1 g is 304.8 s.
Step-by-step explanation:
Given;
half-life of the given Dubnium = 34 s
initial mass of the given Dubnium, m₀ = 500 grams
final mass of the element, mf = 1 g
The time taken for the radioactive element to decay to its final mass is calculated as follows;
![1 = 500 (0.5)^{\frac{t}{34}} \\\\\frac{1}{500} = (0.5)^{\frac{t}{34}}\\\\log(\frac{1}{500}) = log [(0.5)^{\frac{t}{34}}]\\\\log(\frac{1}{500}) = \frac{t}{34} log(0.5)\\\\-2.699 = \frac{t}{34} (-0.301)\\\\t = \frac{2.699 \times 34}{0.301} \\\\t = 304.8 \ s](https://tex.z-dn.net/?f=1%20%3D%20500%20%280.5%29%5E%7B%5Cfrac%7Bt%7D%7B34%7D%7D%20%5C%5C%5C%5C%5Cfrac%7B1%7D%7B500%7D%20%3D%20%20%280.5%29%5E%7B%5Cfrac%7Bt%7D%7B34%7D%7D%5C%5C%5C%5Clog%28%5Cfrac%7B1%7D%7B500%7D%29%20%3D%20log%20%5B%280.5%29%5E%7B%5Cfrac%7Bt%7D%7B34%7D%7D%5D%5C%5C%5C%5Clog%28%5Cfrac%7B1%7D%7B500%7D%29%20%20%3D%20%5Cfrac%7Bt%7D%7B34%7D%20log%280.5%29%5C%5C%5C%5C-2.699%20%3D%20%5Cfrac%7Bt%7D%7B34%7D%20%28-0.301%29%5C%5C%5C%5Ct%20%3D%20%5Cfrac%7B2.699%20%5Ctimes%2034%7D%7B0.301%7D%20%5C%5C%5C%5Ct%20%3D%20304.8%20%5C%20s)
Therefore, the time taken for the radioactive element to decay to 1 g is 304.8 s.
