Answer:
Partial Pressure Of Water Vapor Is 18.65mmHg At 21C0. ... How many liters of H2 gas , collected over water at an atmospheric pressure of 752 mmHg and a temperture of 21 Co, can made from 3.566 g of Zn
Explanation:
Answer:
H- hydrogen
Explanation: Hydrogen is in the first group meaning that it only has 1 valence electron and 1 energy level
<u>Answer:</u> The frequency of the radiation is 33.9 THz
<u>Explanation:</u>
We are given:
Wave number of the radiation,
Wave number is defined as the number of wavelengths per unit length.
Mathematically,
where,
= wave number =
= wavelength of the radiation = ?
Putting values in above equation, we get:
Converting this into meters, we use the conversion factor:
1 m = 100 cm
So,
- The relation between frequency and wavelength is given as:
where,
c = the speed of light =
= frequency of the radiation = ?
Putting values in above equation, we get:
Converting this into tera Hertz, we use the conversion factor:
So,
Hence, the frequency of the radiation is 33.9 THz
Answer:
663 g
Explanation:
Step 1: Write the balanced equation
2 LiOH + CO₂ ⇒ H₂O + Li₂CO₃
Step 2: Calculate the moles corresponding to 825 L of CO₂
At standard pressure and temperature, 1 mole of CO₂ has a volume of 22.4 L.
825 L × 1 mol/22.4 L = 36.8 mol
Step 3: Calculate the moles of H₂O formed from 36.8 moles of CO₂
The molar ratio of CO₂ to H₂O is 1:1. The moles of H₂O formed are 1/1 × 36.8 mol = 36.8 mol.
Step 4: Calculate the mass corresponding to 36.8 moles of H₂O
The molar mass of H₂O is 18.02 g/mol.
36.8 mol × 18.02 g/mol = 663 g
Answer:
The final pressure is 1.01325 kPa
Explanation:
Step 1: Data given
Volume of the metal cylinder = 1550 mL = 1.550 L
Initial Pressure = 70.26 kPa = 0.69341229 atm
Initial temperature = 480 °C = 753 K
The temperature lowers to -237 °C = 36 K
The volume increases to 5114 mL = 5.114L
Step 2: Calculate the final pressure
P1*V1 / T1 = P2*V2/T2
⇒with P1 = the initial pressure = 0.69341229 atm
⇒with V1 = the initial volume = 1.550 L
⇒with T1 = the initial temperature = 753 K
⇒with P2 = the final pressure = TO BE DETERMINED
⇒with V2 = the final volume = 5.114 L
⇒with T2 = the final temperature = 36 K
P2 = 0.0100 atm = 1.01325 Kpa
The final pressure is 1.01325 kPa