That is an annuity and use the attached formula.
Total = 300 * [(1.055)^11 -1] / .055 -300
Total = 300 *
<span>
<span>
<span>
1.8020924036
</span>
</span>
</span>
-1 /.055 -300
Total = 300 *
<span>.8020924036 / .055 - 300
</span>Total = 300 *
<span>
<span>
<span>
14.5834982473
</span>
</span>
</span>
-300
Total =
<span>
<span>
<span>
4375.0494741818
</span>
</span>
</span>
-300
Total =
<span>4075.05
</span>
Answer:
y=2x-8
Step-by-step explanation:
y-y1=m(x-x1)
y-4=2(x-6)
y=2x-12+4
y=2x-8
Answer:
(27.3692 ; 44.6308)
Step-by-step explanation:
Mean, xbar = 36
Standard deviation, s = 11
Sample size, n = 12
Tcritical at 0.2, df = 12 - 1 = 11 ; Tcritical = 2.718
Confidence interval :
Xbar ± Margin of error
Margin of Error = Tcritical * s/sqrt(n)
Margin of Error = 2.718 * 11/sqrt(12) = 8.6308
Confidence interval :
Lower boundary : 36 - 8.6308 = 27.3692
Upper boundary : 36 + 8.6308 = 44.6308
(27.3692 ; 44.6308)
I'd personally go with A and C, The rest don't make too much sense. Don't count on my answer just yet though.
<u>Answer:</u>
The correct answer option is quadratic, because the height increases and then decreases.
<u>Step-by-step explanation:</u>
We are given the following data in the table which represents the height of an object over time:
Time (s) Height (ft)
0 5
1 50
2 70
3 48
We know that in situation where the values increase and then decreases, a quadratic model is used.
From the values given in the table, we can see that the values of height first increased and then decreased with the increase in time.
Therefore, the model used is quadratic, because the height increases and then decreases.
